How would you solve this equation?
2/r^2-r - 1 = 2/r-1
What does 'r' equal?

• put 2/r=k;=>r=2/k ........(i)
  so, the given eqn can be written as-
  k/(2/k)-2/k-1=k-1
  k^2/2-2/k-1=k-1
  k^3-2*(k^2)-4*k=0
  k(k^2-2*k-4)=0
  solving k^2-2*k-4=0
  k=1+sqrt5,1-sqrt5
  now put these above values in eqn (i)to get r
  r=2/(1+sqrt5),2/(1-sqrt5)
• 10 years agoHelpfull: Yes(0) No(0)