In how many ways you can put 4 letters in 2 post boxes. Any no of letter can be posted in box.
a)8
b)4C2
c)24
d) 2P4

• 2 power 4 is the answer. d)2P4 if P is power.
  Reason :
  each letter can be posted in any of 2 post boxes. So its 2*2*2*2 = 16
• 13 years agoHelpfull: Yes(10) No(4)
• since any number of letters can be posted in box
  hence number of permutation of 4 different letters to put in 2 boxes=
  n^r
  here n=4 and r=2
  so 4^2= 4*4= 16.
• 13 years agoHelpfull: Yes(10) No(1)
• 8 ways..
  1st letter in 2 ways+2nd letter in 2 ways+3rd letter in 2 ways+4th letter in 2 ways=8 ways
• 13 years agoHelpfull: Yes(6) No(5)
• 4C2. Because there are 4 letters and 2 post boxes,so the answer should be 4C2
• 13 years agoHelpfull: Yes(3) No(6)
• its definately 8
  4 letters can be placed in 2 boxes as 4*3=12 ways.
  for selection of box their are 2 ways.
  So total ways=12*2=24 ways..
  
• 13 years agoHelpfull: Yes(2) No(2)
• To find the perfect solution follow this link to download the text file
  
  http://uploading.com/files/e68e2fba/tcs2.txt/,tcs2.txt,357 bytes,,Nov 16, 2011,
• 13 years agoHelpfull: Yes(1) No(1)
• we can put every letter by 4 ways.first letter can be post by 4 ways as well as second letter.
  hence total no. of ways=4*4
  
• 12 years agoHelpfull: Yes(1) No(0)
• 4c2..... because we want to select 4 letter to the boxes
• 13 years agoHelpfull: Yes(0) No(5)
• 8 ways because 4+4 =8 ways
• 13 years agoHelpfull: Yes(0) No(5)
• 4c2
  ways Combinations are dealt with by using factorials...The easiest way to explain is to start small
  
  lets say you have 3 numbers...3, 2, 1. You can only arrange them in groups of 2 (in your question, this would be a 2 number box).
  
  The combinations are as follows
  
  3, 2
  3, 1
  2, 3
  2, 1
  1, 3
  1, 2
  
  There are duplicates but that was not a criteria, the question was how many ways, 3, 1 is organized in a different way than 1, 3.
  
  Anyway, there are 6 combinations. The best way to explain how the factorial works here is to say you have 3 numbers, but you can only use 2...so you will go back 2 places on the factorial (A factorial is a number multiplied by one integer less, and then again by 1 less, until arriving at 1)
  
  3! = 3 x 2 x 1. But because you can only use 2 numbers, this becomes 3!/1! = (3 x 2 x 1)/1 = 6.
• 12 years agoHelpfull: Yes(0) No(0)