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5 men can do a certain task working 10 hours a day in 1 day that requires 4 Women 2 days working 8 hours a day and 5 boys 4 days working 5 hours a day. If a contractor hires 20 men, 9 Women, and 10 boys to complete together 1000 such tasks, starting on 1st March, 2000, when will the entire work get over ?
2 nd July
29 th June
30 th June
1 4 th August
5 th July
Read Solution (Total 4)
-
- One task = 5 men 10 hrs 1 day = 50 – man hours
same task = 4 women 8 hrs 2 days = 64 – women hours
same task = 5 boys 5 hrs 4 days = 100 – boy hours
each day total labor available = 20 men (200 man hours) + 9 women (72 women hours ) + 10 boys = 50 boy hours
200 * 100 / 50 + 72 * 100 / 64 + 50
= 400 + 150 + 50
= 600 boy hours
boy hrs task days
100 1 1
600 1000 ?
= 1000 * 100 / 600 = 167 days
from 1st march 167 days = 14th August.
- 13 years agoHelpfull: Yes(5) No(3)
- It is not given , for how much time they all( 20 men, 9 Women, and 10 boys) are working per day to complete together 1000 such tasks .
@ Avanti,
pls check.
72 * 100 / 64 is not equal to 150.
- 13 years agoHelpfull: Yes(4) No(2)
- im nt getting this answer...im bit confuse between 2nd july n 14th august.
so plz guide me... - 12 years agoHelpfull: Yes(0) No(0)
- 14th August
because all other options are not possible.. - 12 years agoHelpfull: Yes(0) No(0)
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