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10 liter of water were added to 10 liter of a 30% strong sol of sulphuric acid, then strenthg of resulting sol is?
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- Now total solution = 20L
sulphuric acid = same i.e. (30/100)*10 = 3L
new percentage = (3/20)*100= 15% - 10 years agoHelpfull: Yes(4) No(0)
- 15
ading water ,vol of water=17l&vol of acid remain 3l
so strenght of sol (3/20)*100 - 10 years agoHelpfull: Yes(3) No(0)
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