Elitmus
Exam
Numerical Ability
Number System
Atul and Bhavi were playing a game of finding a number Atul will give a clue to Bhavi and Bhavi had to find that number the clues were ?
1. It is a 3 digit number
2. The number starts with a digit 1
3. The product of the number is the factor of that number.
Q. How many numbers or combinations are possible?
A) 7
B) 8
C) 11
D) 13
Q. What is the sum of the digit of the highest number so formed ?
a)12
b)14
c)13
d)17
Read Solution (Total 12)
-
- 111,112,115,128,132,135,144,175 total 8 numbers
and sum of highest number is 13...
solution start from 2nd question ..
try from the given options
(A)12= 1+6+5 ,1+7+4 ........ as show on check.
.
.
(c)13= 1+7+5= 175%35 =0 checking all options highest number is 175.
for question 1. we conform that from Q2 number between 111 to 175
check the all number and formed the total 8 number for given condition...
- 10 years agoHelpfull: Yes(24) No(7)
- @Harsha not like that....
The product of the number is the factor of that number it means
1*1*1=1
111/1=111
1*1*2=2
112/2=56
1*1*3=3
113/3=37.666//neglecting number
1*1*4=4
114/4=28.5//neglecting number
1*1*5=5
115/5=23
1*2*8=16
128/16=8 this is the way we can solve the problem totally 8 numbers are got from given condition.
- 10 years agoHelpfull: Yes(7) No(0)
- Ans 1.
SI No. possible comb. product of no. factor of no.
1. 111 1x1x1=1 1
2. 112 1x1x2=2 2
3. 115 1x1x5=5 5
4. 128 1x2x8=16 16
5. 132 1x3x2=6 6
6. 135 1x3x5=15 15
7. 144 1x4x4=16 16
8. 175 1x7x5=35 35
Hence, there are only 8 combination of nos. are possible whose product is equal to factor of the respective no.
Ans 2. The sum of the highest digits number so formed = 175 (i.e 1+7+5)=13 - 9 years agoHelpfull: Yes(6) No(0)
- what about 102,105 etc
- 10 years agoHelpfull: Yes(2) No(5)
- 2nd question answer is sum of the digit of the highest number is 1+7+5(175)=13
1st queston answer is
number is 111,112,115,128,132,144,175
total 7 number is formed - 10 years agoHelpfull: Yes(0) No(3)
- plz explain yaar
- 10 years agoHelpfull: Yes(0) No(0)
- i got it
111 multiply last 2 digits 1x1=1 it divides 111
112 1x2=2 it divides 112
115 1x5=5 it divides 115
like that 128,132,144,175
so total 8 numbers like that hence for a)8 for b)13 - 10 years agoHelpfull: Yes(0) No(3)
- numbers are: 111,112,115,128,132,135,144,175
that is there are 8 nos.
we have to properly check all possibilities one by one.
sum of the digit of the highest no.-13 - 10 years agoHelpfull: Yes(0) No(0)
- @prateek coz man the product of those numbers is 0 which is not a factor of the original number hehe
- 10 years agoHelpfull: Yes(0) No(0)
- @Raushan kumar ..plz explain it
- 10 years agoHelpfull: Yes(0) No(1)
- all the above are not good solutions plz give me the tricks
- 10 years agoHelpfull: Yes(0) No(1)
- http://www.m4maths.com/frequently-asked-placement-questions.php?ISSOLVED=&page=11&LPP=10&SOURCE=elitmus&MYPUZZLE=&UID=&TOPIC=Numerical%20Ability&SUB_TOPIC=Number%20System
- 9 years agoHelpfull: Yes(0) No(13)
Elitmus Other Question