If .2t = 2.2 - .6s and .5s = .2t + 1.1, then s =

• s=3
  
  If .2t = 2.2 - .6s and .5s = .2t + 1.1,
  2t = 22-6s ................(1)
  and
  5s=2t+11 or 2t = 5s-11 ...........(2)
  from (1) and (2)
  22-6s = 5s -11
  11s=33
  s=3
  
  hence
  
• 12 years agoHelpfull: Yes(28) No(0)
• .5s = 0.2t + 1.1
  
  sub 2.2 - .6s for 0.2t
  u get :
  
  0.5s = 2.2 - 0.6s + 1.1
  
  => 1.1 s = 3.3
  
  => s = 3
• 7 years agoHelpfull: Yes(1) No(0)
• s=21
  Ist eq. can be written as 2t=22-6s
  2nd eq. can be written as 5s=20t+11
  Solving, we get s=21
• 12 years agoHelpfull: Yes(0) No(20)
• Take s values and t values across = than substract eq1 and eq2
  S= 11
• 8 years agoHelpfull: Yes(0) No(0)
• we can write the above statements as
  2t-2.2=6s
  2t+1.1=5s
  by observing this we get to know s=-3.3
• 7 years agoHelpfull: Yes(0) No(0)
• t=11-3s
  5s=(11-3s)*2+11
  5s=22-6s+11
  11s=33
  s=3
• 7 years agoHelpfull: Yes(0) No(0)
• 0.2t = 2.2 - 0.6s
  -0.2t = 1.1 - 0.5s
  Substract both equations
  then
  0=1.1-1.1s
  so s=1
• 7 years agoHelpfull: Yes(0) No(0)
• answer is s=3
• 6 years agoHelpfull: Yes(0) No(0)
• 2t+6s=22 and
  2t-5s=-11
  subtracting equations.... we get s=3
• 6 years agoHelpfull: Yes(0) No(0)
• .2t = 2.2-6s ------(1)
  .5s = .2t+1.1 -------(2)
  solving (1) and (2) we get
  11s = 3.3
  so, s = 0.3
• 5 years agoHelpfull: Yes(0) No(1)