At 10 a.m. two trains started traveling toward each other from stations 287 miles apart. They
passed each other at 1:30 p.m. the same day. If the average speed of the faster train exceeded the
average speed of the slower train by 6 miles per hour, which of the following represents the speed of
the faster train, in miles per hour?
A. 38 B. 40 C. 44 D. 48 E. 50

• 44 mph
  
  If s is speed of faster train, then
  3.5*s +3.5*(s-6) =287
  solving it, we get
  s=44 mph
• 12 years agoHelpfull: Yes(59) No(5)
• As two trains are going in opposite direction to each other....their resultant speed will be sum of their speed...suppose slower train has speed "x" and faster train has speed "x+6" mph then according to equation time=(distance/speed) we can write,
  
  287/(x+x+6) =(7/2) (because it takes 3.5 hours to cross each other.)
  solving this we get x=38
  
  and so speed of faster train is x+6=44
  
• 8 years agoHelpfull: Yes(18) No(0)
• distance to be covered by train which will overtake is distance between train+length of the train (to be overtaken)=2000+200=2200 m assuming they are travelling in same direction so only car travelling at higher speed will overtake train travelling at 20 m/s
  relative speed=30-20=10 m/sec(distance travelled by train at 30 m/sec)every sec
  time=distance/speed
  time=2200/10=220 sec
  
  if travelling in oipposite direction speed=20+30=50m/sec
  time=2200/50=44 sec (tie taken by train travelling at 30 m/sec)
  time=2000+300=2300/50=46 sec(time taken by train travelling at 20 m/sec)
  
  _________________
  Ideation without execution is delusion
• 11 years agoHelpfull: Yes(2) No(14)
• goood explanation by binal bhaat
• 7 years agoHelpfull: Yes(1) No(0)
• can anyone explain it clearly...
• 10 years agoHelpfull: Yes(0) No(1)