Accenture
Company
Numerical Ability
Time and Work
A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed?
A. 18 days B. 27 days C. 26.67 days D. 16 days
Read Solution (Total 7)
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- Let the total no of days for completing the work = x
so according to the given condition
(x-10)(1/20) + (x)(1/30) = 1
on solving we will get x = 18 - 12 years agoHelpfull: Yes(33) No(6)
- answer is 18 days.... a quits 10 days before means b wrks for 10 days alone.
Work done By B alone is : 1/30*10=1/3
wrk left=2/3
1/12 wrk is done by A+B in 1 day
2/3 wrk is done in: 12*3/2=18 - 12 years agoHelpfull: Yes(7) No(8)
- 27days.
A and B togthr can do 1/12th work in 1 day.. then they can cmplt in 12days. 10days before it completed, A left. so they togethr workd for 2 days. they workd 1/6th work in 2days. so left work is 5/6th. Bcan do alone 1/30th in 1 day. so B can do 5/6th in 25days. so total no. of days required to cmplt the work is 25+2=27days - 10 years agoHelpfull: Yes(4) No(4)
- A's and B's 10 days work=10*(1/20+1/30)=5/6
Rest of the work is to be completed by B alone=1-5/6=1/6
B's 1 work can be completed in 15 days
B's 1/6 work can be completed in 15*1/6=2.5days(option not given)
- 13 years agoHelpfull: Yes(1) No(14)
- B. 27
as A and B can together in 12 days.. A worked for 2 days. in 2 days A worked 1/10. now left over work is 1-1/10=9/10 . now in 10 days work is done by B. hence, 30*9/10= 27 days
- 9 years agoHelpfull: Yes(1) No(2)
- A B B A+B
20 days 30 days 10 days alone 40/5 = 8 days ==> Total 10+8=18 days
work = LCM(Days)=60
rate 3 2 2 3+ 2 = 5
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Work done = 20 remained = 40 - 9 years agoHelpfull: Yes(0) No(0)
- a.18 days
- 7 years agoHelpfull: Yes(0) No(1)
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