Accenture
Company
Numerical Ability
Time and Work
A, B and C can do a work in 5 days, 10 days and 15 days respectively. They started together to do the work but after 2 days A and B left. C did the remaining work (in days)
A. 1 B. 3 C. 5 D. 4
Read Solution (Total 7)
-
- A's B's & c's work for 2 days=2*(1/5+1/10+1/15)=11/15
Balance work to be done=1-11/15=4/15
c's 1 work can be completed in 15days
c's 4/15 work can be done in 15*4/15= 4 days
Answer= D
- 12 years agoHelpfull: Yes(24) No(2)
- a's 1 day work=1/5
b's 1 day work=1/10
c's 1 day work=1/15
a+B+C's one day work= 1/5+1/10+1/15=2/5
2 day's work= 2* 2/5=4/5 (work done until 2 days)
1/5 work left
c's working capability 1unit work in 15 days
so 1/5 work in 15*1/5=3 days - 9 years agoHelpfull: Yes(2) No(3)
- Option D i.e., 4 days.
- 9 years agoHelpfull: Yes(1) No(0)
- A's B's & C's work for 2 days=2*(1/5+1/10/1/15)=19/30
Bal. work to be done by c alone=1-19/30=11/30
C's 1 work can be completed in 15 days
c's 11/30 work can be completed in 15*11/30=11/2 days=5.5days(option is not there) - 13 years agoHelpfull: Yes(0) No(19)
- Ans is D.4
- 9 years agoHelpfull: Yes(0) No(0)
- 1/5+1/10+1/15 = 11/30
A's B's & c's work for 2 days=2*(11/30)=11/15
Balance work to be done=1-11/15=4/15
c's 4/15 work can be done in 15*4/15= 4 days
Answer= D - 5 years agoHelpfull: Yes(0) No(0)
- one day work of all 3 is = 1/5+1/10+1/15=11/30
for 2 days work= 11/30*2=11/15
remaing work is = 1-11/15=4/15(which is to be done by c)
so c's work = 4/15*15=4 days - 3 years agoHelpfull: Yes(0) No(0)
Accenture Other Question