what is the probability of obtaining a full house 3 of one 2 of another

choose(3 of one)=3C1
choose(2 OF ANOTHER)=2c2
SO PROBABILITY=3c1+2c2=3+1=4.
probabillity of obtaining a full house is 4
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yogesh and rishab how guys are taking 13c1 4c3 on what bases ur taking these values?
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plz give sol anyone
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13c1*4c3*12c1*4c2/52c5
=13*4*12*6/52c5
=3744/2598960
=0.001440

ihope this is the right answer.
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a full house is 3 of one type of card and 2 of another type.
THEN...............
Pick a type of card: 13 ways
Pick 3 of that type of card: 4C3=4 ways
Pick a different type of card: 12 ways
Pick 2 of that type: 4C2=6
# of "full-house hands" = 13*4*12*6=3744
# of 5 card hands: 52C5=2598960
Prob(full house)= 3744/2598960=0.00144057...
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1c13*3c4*1c12*2c4/5c52= 0.1441
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select(3 of 1)=3c1
select(2 of 1)=2c1
so p=3c1+2c1=5
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Answer is 1/5=0.2
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(13c1.4c3.12c1.4c2)/52c5= 0.1441
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3c1+2c2=4
3!=6
therefore 4/6 is the answer
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question to clear kar de pehle chu...
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yogesh i cut your dick and hung on bakery oven then your dick tikka is ready then i fed these to #YOGESH family.
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what is the probability of obtaining a full house (3 of one, 2 of another)?