Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

• A+B+C = 90
  (A-10) : (B-10) : (C-10) => 1:2:3
  Total age before 10 years = 90-30 = 60
  A's age before 10 years = 60*1/(1+2+3) = 10
  B' age before 10 years = 60*2/6 = 20
  C' age before 10 years = 60*3/6 = 30
  
  B's present age = 20+10 = 30
  
  Ans : 30
• 9 years agoHelpfull: Yes(40) No(3)
• Let their ages 10 years ago is x, 2x and 3x years.
  (x + 10) + (2x + 10) + (3x + 10) = 90 hence x= 10
  B’s present age = (2x + 10) =30 years.
  
  ANSWER: 30
• 9 years agoHelpfull: Yes(27) No(0)
• 1x+2x+3x=90 ten years ago so x-10+2x-10+3x-10=90
  6x-30=120
  x=20
  B age is 2x So B=40
• 9 years agoHelpfull: Yes(7) No(11)
• A+B+C=90
  THEN AGE OF B = 90*2/6=30
• 9 years agoHelpfull: Yes(3) No(0)
• ans=30
  let x be the common age of all the three
  ten years their ratios are let x,2x,3x
  at present the ages of a,b,c are x+10,2x+10,3x+10
  total ages of a,b,c at present =90
  =>x+10+2x+10+3x+10=90
  =>6x+30=90
  =>x=10
  now ages of a,b,c at presant are 20,30,40 respectively
  then age of b at present =30
• 9 years agoHelpfull: Yes(2) No(1)
• lets take ages as 1x, 2x, 3x
  add all 1x+2x+3x=90, then x=15.
  now 2x=30, so ans=30.........
  
• 9 years agoHelpfull: Yes(2) No(0)
• A+B+C=90
  10 years ago, A-10:B-10:C-10::1x:2x:3x
  so, A=x+10 B=2x+10 C=3x+10
  
  A+B+C=x+10+2x+10+3x+10=6x+30
  this implies 6x+30=90 hence x=10
  
  age of B is 2x+10=2(10)+10=30years
  age of A is x+10=10+10=20years
  age of C is 3x+10=3(10)+10=40years
  totally we get 90 years
  
• 9 years agoHelpfull: Yes(1) No(1)
• The answer is 30.
  suppose their ages 10 years ago was x, 2x and 3x years.
  (x + 10) + (2x + 10) + (3x + 10) = 90 hence x= 10
  
  so B’s present age = (2x + 10) =30 years.
• 9 years agoHelpfull: Yes(1) No(0)
• Ans is 30 years
• 9 years agoHelpfull: Yes(1) No(0)
• A - 20
  B - 30
  C - 40
  AND 10 years ago age was
  a - 10
  b -20
  c- 30
• 9 years agoHelpfull: Yes(0) No(4)
• ten yrs ago:x+2x+3x=90-30
  6x=60
  x=10
  present age of b=2x+10=30
  
• 9 years agoHelpfull: Yes(0) No(1)
• 30 yrs. let 20,30,40 be the ages of A
• 9 years agoHelpfull: Yes(0) No(0)
• present age ie is total-->90
  so before 10 years it will be 90-30=60(coz 10 years minus from all 3)
  now
  1x+2x+3x=60
  6x=60
  x=10
  b's age 10 years ago is 2*10=20
  present age is 20+10=30
  ans=30
• 9 years agoHelpfull: Yes(0) No(0)
• present ages: 15:30:45 as 10 years ago their ages in the ratio 1:2:3 so sum finally 15+30+45=90 So, B's age is 30
• 9 years agoHelpfull: Yes(0) No(0)
• 45..
  45 satisfies the question
  
• 9 years agoHelpfull: Yes(0) No(3)
• Today
  A+B+C = 90 yrs
  
  10 yrs ago
  A B C
  x + 2 x + 3x = 60
  6x = 60
  x = 10
  Therefore today B = 20+ 10 = 30
• 8 years agoHelpfull: Yes(0) No(0)
• At Present A+B+C=90
  10 Years ago (A-10):(B-10):(C-10)=1:2:3
  total age before 10 years=60 years
  so x+2x+3x=60 =>x=10
  B's age before 10 years=2 x 10=20
  At present 20+10=30 years
• 8 years agoHelpfull: Yes(0) No(0)
• 30 is a ans
  
  
• 7 years agoHelpfull: Yes(0) No(0)
• Total ages of A+B+C=90 yrs
  ten years ago the ratios of their ages was 1:2:3
  so let there ages 10 years ago be
  x-10 +2x-10 + 3x-10 = 90
  6x-30=90
  6x=90+30
  6x=120
  x=20
  therefore Age of B at present is 2x-10=2(20)-10
  =40-10
  =30;
• 7 years agoHelpfull: Yes(0) No(0)
• x+2x+3x=90-60
  6x=60
  x=60/6
  x=10
  age of b at present=2x+10=2*10+10=30
• 6 years agoHelpfull: Yes(0) No(0)
• Sum of present ages(A+B+C)= 90
  Ratio of 10 years ago A:B:C= 1:2:3
  =>sum of 10 years ages= 90-30=60
  now ratio 1+2+3--------60
  this gives 6_____60 => 1_____10
  B's age of 10 years ago = 10*2= 20
  B's present age = 20+10=30
• 6 years agoHelpfull: Yes(0) No(0)
• A=1;
  B=2;
  C=3;
  B=2/6 /* 2/(1+2+3) */
  90*2/6;
  90*1/3;
  =30
• 4 years agoHelpfull: Yes(0) No(0)