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If 3 numbers are in the ratio of 3:2:5 such that sum of their squares is equal to 1862. what is the middle number?
Option
a) 25
b) 14
c) 30
d) 34
Read Solution (Total 28)
-
- Let the numbers are 3x, 2x, 5x
Now,
(3x)^2 + (2x)^2 + (5x)^2 = 1862
=> x^2 = 49
=> x = 7
middle number is 2x = 2 * 7 = 14 - 10 years agoHelpfull: Yes(38) No(0)
- Let numbers be 3x, 2x, 5x
Now 9x2+4x2+25x2=1862
X2=1862/38
X=7
So, second number=2*7=14
- 10 years agoHelpfull: Yes(10) No(1)
- let the no.s be 3x, 2x and 5x
given: (3x)^2+(2x)^2+(5x)^2=1862
Solving above equation, we get
x=7
so, middle no. i.e., "2x=14" - 10 years agoHelpfull: Yes(3) No(0)
- From options
b) 14
3 : 2 : 5
21 : 14 : 35
21^2 + 14^2 +35^2
441 + 196 + 1225 = 1862
Alternate method
middle number is given
if 2 parts = 25 / 14 / 30 /34
then 1 part is 12.5 / 7 / 15 / 17
1862 must be divisible by any of the above
1862 is not divisible by 12.5 so option a is not possible
" " is divisible by 7 so option b - 10 years agoHelpfull: Yes(2) No(7)
- 14
(3x)^2+(2x)^2+(5x)^2=1862
x^2=49
x=7
2*x=14 - 10 years agoHelpfull: Yes(2) No(0)
- let the no.be x
so the ratio will be
3x:2x:5x
Sum of their squares 9(x)^2 + 4(x)^2 + 25(x)^2 = 1862
38(x)^2=1862
x=7, so the middle no will be 7*2=14
Ans:-14 - 10 years agoHelpfull: Yes(2) No(0)
- b) 14
(3x)^2+(2x)^2+(5x)^2=1862
x=7
- 10 years agoHelpfull: Yes(2) No(1)
- b)=14
let the num be x
9x^2+4x^2+25x^2=1862
x^2=49===>x=7
then middle num=7*2=14 - 10 years agoHelpfull: Yes(2) No(0)
- the 3 nos are in the ratio 3:2:5
so let the nos be 3x 2x 5x
(3x)^2+(2x)^2+(5x)^2=1862
9x^2+4x^2+25x^2=1862
38x^2=1862
x=7
the middle term is 2x=2*7=14
therefore b is the ans - 10 years agoHelpfull: Yes(2) No(0)
- 30
15*2=30
1583=45
15*5=75
The sum of squares is 1862
45^2+30^2+75^2=1862 - 10 years agoHelpfull: Yes(1) No(7)
- The answer for this question is 14.
- 10 years agoHelpfull: Yes(0) No(1)
- As 3 numbers are in the ratio of 3:2:5,
Let the numbers are 3x, 2x, 5x
Now, so the ratio will be
3x:2x:5x
As sum of their squares is equal to 1862
Now,
(3x)^2 + (2x)^2 + (5x)^2 = 1862
=> x^2 = 49
=> x = 7
middle number is 2x = 2 * 7 = 14
b) 14
- 10 years agoHelpfull: Yes(0) No(0)
- suppose no. is 3x,2x,5x
ans is b - 10 years agoHelpfull: Yes(0) No(1)
- let the num be x
9x^2+4x^2+25x^2=1862
x^2=49===>x=7
then middle num=7*2=14 - 10 years agoHelpfull: Yes(0) No(0)
- let the ratio common factor equals to x.thus the nos are 3x,2x,5x
thus 38 x^2=1862(as sum of the squares=1862)
thus x=14 - 10 years agoHelpfull: Yes(0) No(0)
- x=7*2=14 is da ans
- 9 years agoHelpfull: Yes(0) No(0)
- let the numbers are 3x,2x,5x
then (9x^2+)+4x^2+25x^2=1862
x^2=49
x=7
middle number=2x=14 - 9 years agoHelpfull: Yes(0) No(0)
- check with the options. if u take 14 as middle number
the ratio will be 21:14:35
check sum of squares of these numbers will gives u 1862
remaining will not give
so,answer is 14 - 9 years agoHelpfull: Yes(0) No(0)
- root49*2=14
- 9 years agoHelpfull: Yes(0) No(0)
- root(1862/(3^2+2^2+5^2))= root(1862/38)= 7
middle no= 7*2= 14 - 9 years agoHelpfull: Yes(0) No(0)
- 3:2:5
so sum of squares of these numbers is (3x)(3x)+(2x)(2x)+(5x)(5x)=1862
38(x^2)=1862
x^2=1862/38
x^2=49 therefore x=7
second num is 2(x)=2(7)=14
ans is (b) - 9 years agoHelpfull: Yes(0) No(0)
- 3x,2x,5x
9x^2+4x^2+25^2=1826
x^2=49
x=7
middle no 2x=14 - 9 years agoHelpfull: Yes(0) No(0)
- 9+4+25=38
4/38*1862=196
root of 196=14 Ans - 9 years agoHelpfull: Yes(0) No(0)
- Let the three nos. be 3x , 2x & 5x
So a.t.q,
(3x)^2 + (2x)^2 +(5x)^2 =1862
x^2 (38)= 1862
x^2=1862/38
x^2=49
x=7
therefore, the middle no. is 2x=2*7=14
ans. is 14 - 9 years agoHelpfull: Yes(0) No(0)
- 14
9x^2+4x^2+25^2=1862
38x^2=1862
x=7
middle number=7*2=14
- 9 years agoHelpfull: Yes(0) No(0)
- Take b)14
then 21,14,35 are three numbers then squares sum = 1862. - 9 years agoHelpfull: Yes(0) No(0)
- b is the answer
3:2:5 their sum squares =1862
multiply with 7 by each=21:14:35
21*21=441,14*14=196,35*35=1225
441+196+1225=1862 so mid value=14
- 8 years agoHelpfull: Yes(0) No(0)
- 1862/38=49
x=7
2*7=14 - 7 years agoHelpfull: Yes(0) No(0)
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