PAS
*RBQ
----------------
SBKW
ASAA
SEPB
---------------
SQSKAW

• Lets start the solutioon:
  1. as K+A=_A and there is no carry from right(as there is only W). therefore, K=0.
  2. Now 2*B + A = _0. now this _ can either be 1 or 0.
  now if we take this sum(2*B+A)=20. then possible values of (A & B) can be
  (B,A)=(6,8)or (7,6) or (8,4).
  now if we take B=8 and A=4.
  3. As we can see P4S*8= 4S44.now as we know 8*3=24. therefore S=3.
  so know this multiplication becomes P43*8=4344. now as 8*5=40. therefore P=5.
  Continue accordingly. You will get the answer.
• 10 years agoHelpfull: Yes(18) No(0)
• plz expand this multiplication..
  
  Q*S = b , Q*A +c =k , Q*P +c = sb/.....1
  
  B*S =A , B*A +c = A, B*P +c = AS .......2
  
  R*S = B ,R*A +c =P ,R*P +c = SE .........3
  
  from .... 2 it follow the more pattern so solve this by trial method.
  
  8*3 = 4 ,8*4 + 2 = 4 , 5*8 +3 = 43, now put the value the u can solve this very easily ...
  answer is...
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  B*S = A ,B*S + c = A, B*P +c = AS.......2 c stands for carry it is may or may nt
  
  R*S = B , R*A +c = p , R*P +c = SE .....3
  
  from ....2 it is follow the more pattern so u can find the value as..
  
  8*3 = 4 , 8*4 + 2 = 4, 5*8 + 3 = 43 ,
  
  now u fill these values u can solve this problem easily ..
  
  so 543
  *687
  -----------
  3801
  4344
  3258
  -------------- hello dear currently this type of question frequently asked in
  373041
  --------------
  
  --------
  
  
• 10 years agoHelpfull: Yes(15) No(18)
• 543
  *687
  -------
  3801
  4344
  3258
  ------
  373041
  ------
• 10 years agoHelpfull: Yes(12) No(2)
• how to solve these? :(
• 10 years agoHelpfull: Yes(12) No(1)
• Raushan ur hit & trial method is gud bt will u plz tell me iz there be another method to solve equation 2????
• 10 years agoHelpfull: Yes(4) No(1)
• how we will get P=5,A=4,S=3,R=6,B=8,Q=7
• 10 years agoHelpfull: Yes(3) No(2)
• 543
  *687
  -------
  3801
  4344
  3258
  ------
  373041
  
  Solving this problem, I noticed one thing that, look in the 5th column from left in question. It is K+A=A.
  This would be possible only when K=0 (you can check).
  Similarly, look in the 4th column it is B+A+B = K. Here also K=0, so the values of B, A, B will be (1,8,1), (2,6,2), (3,4,3), (4,2,4), (6,8,6), (7,6,7), (8,4,8), (9,2,9). Check each n every value. You will get the correct substitute in (8,4,8). And then you can compute easily the rest ones...
  
  It took hardly 25-35 min for me to solve.
  I hope you have understood my explanation.
  Thank you.
• 9 years agoHelpfull: Yes(3) No(0)
• solution is:543
  *687
  ------------------------
  3801
  4344-
  3285--
  ----------------------------
  373041
  ----------------------------
• 10 years agoHelpfull: Yes(2) No(0)
• P=5,A=4,S=3,R=6,B=8,Q=7.......SBKW=3801,ASAA=4344,SEPB=3258....SQSKAW=373041
• 10 years agoHelpfull: Yes(1) No(4)
• 543
  687
  -------
  3801
  4344
  3258
  -------
  373041
• 10 years agoHelpfull: Yes(1) No(0)
• 543
  *687
  -----------
  3801
  4344
  3258
  ----------
  373041
• 10 years agoHelpfull: Yes(1) No(0)
• first see that a+k=a it means k=0.now put k=0 everywhere in problem .now u willsee
  b+a+b=0b should not be 5 because then u will not get 0.so try to put 2,3,4,6,7,8 simultaneously put a=6,4,2,8,6,4. and also try to check pas*b with these nos.once u get a and b everything will be clear.
  543
  *687
  -----
  3801
  4344
  3258
  ------
  373041
• 9 years agoHelpfull: Yes(1) No(0)
• 543
  *687
  3801
  4344
  3258
  373041
  K=0, u can directly k+a=a.2b+a=0,b=8 .and a=4
  S+p=
• 9 years agoHelpfull: Yes(1) No(0)
• try to start with second step because AA is same..so think
• 10 years agoHelpfull: Yes(0) No(0)
• if any other method the conventional one... pls share.. hit and trail doesnt comes easily..
• 10 years agoHelpfull: Yes(0) No(0)
• akshay u said
  2*B + A = _0. now this _ can either be 1 or 0.
  now if we take this sum(2*B+A)=20.
  if _ can be 0 or 1, why have taken it as 2 in 2*B+A=20
• 10 years agoHelpfull: Yes(0) No(0)
• Its 543 * 687
  Question can be initiated from K + A = A (hence only K=0 satisfies d condition)
• 10 years agoHelpfull: Yes(0) No(0)
• in this problem see the k+A=A means that k=0,A= any number 0 to 9 . after that see B+A+B=A and take value of B and A from your assumption satisfy two condition PAS*B=ASAA, B+A+B=A then you will get value of B is 8 and value of A=4 and p=5. after finding these value , value of R and Q will easily get . so that required solution of this ( 543*687 )
• 9 years agoHelpfull: Yes(0) No(0)
• 543
  687
  ..........
  3801
  4344
  3258
  ............
  373041
• 9 years agoHelpfull: Yes(0) No(1)
• 543
  687
  ..........
  3801
  4344
  3258
  ..............
  373041
• 9 years agoHelpfull: Yes(0) No(0)
• Hey guyz...seriously plz any1 tell me to how solve dese type of questions.....???xcluding hit n trial method....
• 9 years agoHelpfull: Yes(0) No(0)