if 21x+24y=c,is c a wholenumber?
i)x is a multiple of 42
ii)y is a multiple of 48

• It requires both option 1 and 2,
  because whule number are 0,1,2,3,..... and so on
  
  ->so if we know x is a multiple of 42 then it might be possible that y be any fraction which gives (24*y) a fraction value so then c will not be a whole number.
  
  ->also if we take only y is a multiple of 48 then also same condition can arise.
  
  so for proper answer we must have to know both x and y.
• 10 years agoHelpfull: Yes(43) No(8)
• x is a multiple of 42 it may be negative or positive. also same for y. so we cant say that c is always whole number. it also be negative.
• 10 years agoHelpfull: Yes(17) No(3)
• it may be both are not sufficient to answer this question
  
• 10 years agoHelpfull: Yes(6) No(15)
• Both statements are no sufficient enough even taken together because we can get that c is a natural number but we cannot get to know whether c attains the '0' value at any instance which is a major difference between a natural number set and a whole number set.
• 10 years agoHelpfull: Yes(6) No(8)
• it requires both. as long as x or y isnt negative, the c will always be whole number
• 10 years agoHelpfull: Yes(3) No(3)
• both are not sufficient to ans the ques bcz we wil nt be able to determine whether the number formed starts frm 0 (which is necessary to satisfy to be a whole number) or 1.
• 10 years agoHelpfull: Yes(2) No(4)
• 1 and 2 are not sufficient to give the soln.
• 8 years agoHelpfull: Yes(0) No(1)
• Mithun Kesari sir you are absolutely right
• 8 years agoHelpfull: Yes(0) No(0)
• answer is both statements together are not sufficient!
  explanation:
  here nothing is being stated about x and y whether they are positive or negative
  as they (statements)can't stand alone ,considering both statements together:
  case(i):if we take x=42,y=48 and put in the equation 21x+24y=c=>c is a whole no.
  case(ii): if we take x=-42,y=-48=>c=-ve=>c is not a whole number
• 7 years agoHelpfull: Yes(0) No(0)