Who come next in the series ?
JAZ, LEX, NIV, POT

a. RUR
b. QUR
c. RUS
d. SUR
e. PUR

• 1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for next 2 words
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  So the next word is RUR
  
  Ans: 1) RUR
• 9 years agoHelpfull: Yes(65) No(2)
• option 1
  j,l,n,p,r
  a,e,i,o,u
  z,x,v,t,r
  all the above alphabets are placed alternativaly
• 9 years agoHelpfull: Yes(5) No(2)
• here
  first digit +2
  second digit +3
  last digit -2
  so ans will become rur
• 9 years agoHelpfull: Yes(3) No(0)
• answer is RUR.
  reason: J+2=L, L+2=N,N+2=P, P+2=R
  A+4=E, E+4=I,I+6=O, O+6=U
  Z-2=X, X-2=V, V-2=T, T-2=R
  
• 9 years agoHelpfull: Yes(3) No(2)
• counting from A-Z we get
  J A Z - 10 1 26
  L E X - 12 5 24
  N I V - 14 9 22
  P O T - 16 15 20
  
  1ST letter increase of 2
  2nd letter increase of 4 twice then increase of 6 twice
  3rd letter decrease of 2
  therefore we get
  
  18 21 18 -- R U R
  
• 9 years agoHelpfull: Yes(3) No(1)
• J,L,N,P so nxt R
  A,E,I,O so nxt U
  Z,X,V,T so nxt R
  
• 9 years agoHelpfull: Yes(2) No(0)
• 1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for next 2 words
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  So the next word is RUR
  
  Ans: 1) RUR
• 9 years agoHelpfull: Yes(2) No(0)
• alphabetically first comes J,then after one comes l and after one comes N and so on..so after P it has to be R. then for second letter all the vowels are taken. A E I O already used,so U is left.then 3rdly it started with the last alphabate and skipped one periodically backwards! So after T it has to be R!
  the ans. is 1. RUR
• 9 years agoHelpfull: Yes(2) No(1)
• 1.RUR
  if take series ...it know its
  
• 9 years agoHelpfull: Yes(1) No(2)
• 1....RUR J+2POSITIONS RIGHT=L L+2POSITIONS RIGHT=N JKLMNOPQR
  TTHEN VOWELS AEIOU Z+2POSITIONS LEFT=X X+2POSITIONS LEFT=V AND SO ON T+2POSITIONS LEFT=R
• 9 years agoHelpfull: Yes(1) No(1)
• J NEXT L
  L NEXT N
  N NEXT P
  AND LAST LETTER Z PREVIOUS X
  X PREVIOUS V
  V PREVIOUS T
  T PREVIOUS R
  SO ANSWER IS (1) RUR
  
• 9 years agoHelpfull: Yes(1) No(2)
• j,,l,,n,,p,,r -> 1st letters of each word
  Similarly last wors are in backward form:
  z,,x,,v,,t,,r
  therefor answer is:
  (1)RUR
• 9 years agoHelpfull: Yes(1) No(0)
• first letter inc by 1 in all words
  second letter inc by 4 in 1st two words and remaining two words inc by 6
  third letter decrement by 1 in all words
• 9 years agoHelpfull: Yes(1) No(0)
• Correct answer is (1)RUR
  
  1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for next 2 words
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  So the next word is RUR
  
  Ans: 1) RUR
• 9 years agoHelpfull: Yes(1) No(2)
• jaz=10 1 26;
  lex=12 5 24;
  niv=14 9 22;
  pot=16 15 20;than next is 18 21 18 because for first word inc by 2 and for 2nd word first 2 inc by 4 and second 2 inc by 6 and for 3 word dcr by 2
• 9 years agoHelpfull: Yes(1) No(0)
• FIRST PLACE INCCREASE BY 2 LETTERS
  2ND PLACE ARE VOWELS
  3RD DECREASES BY 2
  SO P+2=R, O->U, T-2=R
  ANS=RUR
• 9 years agoHelpfull: Yes(1) No(0)
• I DON'T KNOW ANS
• 7 years agoHelpfull: Yes(1) No(0)
• it will be 1)RUR
  1st letter inc by 1
  2nd inc by 4 for 2 words and then by 6 for next 2 words
  3rd decreases by 1
• 9 years agoHelpfull: Yes(0) No(0)
• 1st letter is j l n p r - leaves 1 letter after each letter
  2nd word is vowels a e i o u
  3rd letter is z x v t r - from reverse it leaves 1 letter after each letter
  Hence answer is (A) ...
• 9 years agoHelpfull: Yes(0) No(0)
• 1. First letter
  J - l - M - P - R
  Secnd letter
  AEIO u... Vowels
  Third letter
  Z,X,V,TR i reverse order
  
• 9 years agoHelpfull: Yes(0) No(0)
• RUR, 2 letter after R, 3 letter after o, 2 letter before T
• 9 years agoHelpfull: Yes(0) No(0)
• 1..with the help of alphabatical series
• 9 years agoHelpfull: Yes(0) No(0)
• J K L M N O P----J L N P R T
  Z Y X W V U T S R---Z X V T R
  U--COMMON
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans will be (3).. ist letter- J(K)L, L(M)N, N(O)P,P(Q)R. SO IST LETTER WILL BE R THEN 2ND LETTER WILL BE 5TH VOWEL... A, E, I, O, U... THAT MEANS U..... RUS..
• 9 years agoHelpfull: Yes(0) No(3)
• Ist and lasy latter has diff of 2
  And middle one are vobel
  So the ans is (1).
• 9 years agoHelpfull: Yes(0) No(0)
• option1 RUR
• 9 years agoHelpfull: Yes(0) No(0)
• the middle letters are A,E,I,O,U, VOWELS
  the first letters are having difference of 2 J,k,L,m,N,o,P,q,R
  the last letter are having the difference of 2 FROM BACK SIDE OF ALPHABET Z,X,U,T,R
• 9 years agoHelpfull: Yes(0) No(0)
• rur first letter is moved two step forward,third letter moved two step backward while second letter follows 4 4 6 6
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1.rur
  steps.we will check only for first and last one and not the middle one because each option contains it.
  then,considering the first letter there is gap of one letter. so after p comes r.
  
• 9 years agoHelpfull: Yes(0) No(0)
• RUR. J thn L its alternative. so aftr P it wil b R. th for Z its again inversely alternative so b4 T, S is negltcd... so R wil cum..
• 9 years agoHelpfull: Yes(0) No(0)
• 1.RUR
  just take the alternate alphabets.and for the middle alphabet it is the last vowel i.e U.
• 9 years agoHelpfull: Yes(0) No(0)
• j is increasing by 2 i.e l,q is increasing by 2 i.e q in the same way simply after
  p there is a r and i.e the result RUR
• 9 years agoHelpfull: Yes(0) No(0)
• 1) RUR
  j+2=l
  l+2=n
  n+2=p
  p+2=r
  z-2=x-2=v-2=t-2=R
• 9 years agoHelpfull: Yes(0) No(0)
• answer is RUR.
  1st letter is at difference of 2 with previous
  2nd letter is at difference of 4 with previous
  3rd letter is at difference of 2 in an opposite direction
• 9 years agoHelpfull: Yes(0) No(0)
• RUR is the right answer
• 9 years agoHelpfull: Yes(0) No(2)
• RUR
  by using alphabets position
  
• 9 years agoHelpfull: Yes(0) No(2)
• N+2=P,I+6=0,22-2=T so P+2=R,0+6=U,T-2=R so ans is RUR
• 9 years agoHelpfull: Yes(0) No(0)
• (1) RUR
  J+2=L;L+2=N;N+2=P;P+2=R
  A+4=E;E+4=I;I+6=O;O+6=U
  Z-2=X;X-2=V;V-2=T;T-2=R
  i.e. RUR
• 9 years agoHelpfull: Yes(0) No(0)
• intially word starting with j then next word is strting from L next word is again strting with N......so key point is here is interval of 1 between these two no..so
  only we hv see the option 1 and 3..now checking for last later from each word again interval of 1 from reverse..at the end we have only RUR.
• 9 years agoHelpfull: Yes(0) No(0)
• ans is: RUR
  J+2=L ,L+2=N, N+2=P, P+2= R
  A+4=E ,E+4=I, I+6=O, O+6= U
  Z-2=X ,X-2=V, V-2=T, T-2= R
• 9 years agoHelpfull: Yes(0) No(0)
• every first letter in question are one gap to another i.e., in first term J is present and in next term" by leaving K it take L" and so on......... similarly after leaving on alphabet next to P ' WE GET THE ANSWER STRATING WITH R' so the answer is RUR
• 9 years agoHelpfull: Yes(0) No(1)
• 1,between J n L K is missing, L n N M is missing,N n P O is missing so after that R is there similarly from last one R is there so only 1 optn. is belongs to that.
• 9 years agoHelpfull: Yes(0) No(0)
• 1.RUR write down A-Z check sequence will be able to reject the wrong ones seeing for 1st char from 'A' u get 'R' and for 3rd char from 'Z' u get 'R'.
• 9 years agoHelpfull: Yes(0) No(0)
• 
  JAL,(J+2)(A+4)(Z-2),(L+2)(E+4)(X-2),(N+2)(I+4)(V-2),(P+2)(O+4)(T-2)
  ans=RUR
• 9 years agoHelpfull: Yes(0) No(0)
• J-L-N-P- FOLLOWS R,that is the alternate alphabets..
• 9 years agoHelpfull: Yes(0) No(0)
• 1ubuobobibuboub
  iojhiug
• 9 years agoHelpfull: Yes(0) No(0)
• j+2=L,L+2=n,n+2=p,p+2=r(1st letter)
  a+4=e,e+4=i,i+6=o,o+6=u(2nd letter)
  z-2=x,x-2=v,v-2=t,t-2=r(3r letter)
  hence the next word is RUR
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for next 2 words
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  So the next word is RUR
  
  Ans: 1) RUR
• 9 years agoHelpfull: Yes(0) No(0)
• 3 3 5 5 ->r
  zxvtr
  rur answer
• 9 years agoHelpfull: Yes(0) No(0)
• 1 option as JAZ,LEX,NIV,POT as we observe 1st letters have letter gaps among them
  j k l m n o p q r so 1st letter is R So within 2 options consider again 3rd letter from back with 1 letter gap z,y,x,w,v,u,t,s,r so 3rd letter is R
• 9 years agoHelpfull: Yes(0) No(0)
• option1:RUR
• 9 years agoHelpfull: Yes(0) No(0)
• 1st letter increases by 2 n last decreases by 2 . henc eans is (1) RUR
• 9 years agoHelpfull: Yes(0) No(0)
• z-x-v-t-r(last)
  a-e-i-o-u(middle)
  j-l-n-p-r(1st)
  ans:RUR
• 9 years agoHelpfull: Yes(0) No(0)
• JAZ=37
  J=10 A=1 Z=26 J+A+Z=37
  QUR=41---DIFFERENCE=4
  NIV=45---4
  POT=51-------6
  ANSWER IS RUR=57
  
• 9 years agoHelpfull: Yes(0) No(0)
• j+2=l,l+2=n,p+2=r
  nd 2nd letter
  a+4=e,e+4=i,i+6=o,o+6=u
  3rd letter will b
  z-2=x,x-2=v,v-2=t,t-2=r
  so ans will b RUR
• 9 years agoHelpfull: Yes(0) No(0)
• The ans is 1 i.e RUR
  If u c the middle letter is b/w two letters which r double 2 each other.
• 9 years agoHelpfull: Yes(0) No(0)
• rur
  there is a pattern that in next word all the letter are increased only the last letter is in decreasing order
• 9 years agoHelpfull: Yes(0) No(0)
• 1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for nxt 2 wrds
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  the next word is RUR
• 9 years agoHelpfull: Yes(0) No(0)
• rur
  observed the sequence
• 9 years agoHelpfull: Yes(0) No(0)
• j+a+z=10+1+26=37
  l+e+x+12+5+24=41
  n+I+v=14+9+22=47
  p+o+t=16+15+20=51
  so next no. will be 57
  i.e, r+u+r=18+21+18=57
  ans.=(1)RUR
• 9 years agoHelpfull: Yes(0) No(0)
• rur
  diffrnc in 1st letters=1 (jkl)
  difference in last letter= -1 (rst,tuv,vwx,xyz)
  and diff in mid is 3,3,5,5
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1.RUR
  Jk Lm No Pq R
  AbcdE fghI jklmnO pqrst U
  Zy Xw Vu Ts R
• 9 years agoHelpfull: Yes(0) No(0)
• j+2=l,l+2=n,n+2=p,p+2=r
  A+4=E, E+4=I,I+6=O, O+6=U
  Z-2=X, X-2=V, V-2=T, T-2=R
  RUR
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1) RUR
  [Saraswathy]
  1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for next 2 words
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  So the next word is RUR
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans :RUS
  
  
  
• 9 years agoHelpfull: Yes(0) No(6)
• ans is pur
• 9 years agoHelpfull: Yes(0) No(1)
• becoz , first letter of each word diference in first letter is one, and last letter in reverse difference also is one
  ex: j skip the letter k then next word first word is l and so on;
  end z skip y next letter is x and so on
• 9 years agoHelpfull: Yes(0) No(1)
• b) QUR
  Q comes after P and Q
  
• 9 years agoHelpfull: Yes(0) No(3)
• a RUR The sequence is 18,21,18
• 9 years agoHelpfull: Yes(0) No(0)
• ans is a
  RUR
• 9 years agoHelpfull: Yes(0) No(0)
• RUR...
  D middle letter being d vowels
  The other two being alternative alphabets in ascending nd descending ordr
• 9 years agoHelpfull: Yes(0) No(0)
• a is the ans
  
• 9 years agoHelpfull: Yes(0) No(0)
• RUR .......................
• 9 years agoHelpfull: Yes(0) No(0)
• answer is RUR
  first letter should be placed in next word in second letter,second letter is placed in 4th letter and last letter is placed inprevious 2 letters,so RUR is the answer
  
• 8 years agoHelpfull: Yes(0) No(0)
• J A Z - 10 1 26
  L E X - 12 5 24
  N I V - 14 9 22
  P O T - 16 15 20
  RUR - 18 21 18
• 8 years agoHelpfull: Yes(0) No(0)
• RUR
  
  the First letter in all series are the alternate letters J,L,N,P,R
  the second letter in all series are the A,E,I,O,U
  the third letter in all series are the decreasing alternate letter from Z i.e Z,X,V,T,R
• 8 years agoHelpfull: Yes(0) No(0)
• a.rur.....
• 8 years agoHelpfull: Yes(0) No(0)
• j,k,l,m,n,o,p,q next is r
  we wont think for the middle term
  (r),s,t,u,v,w,x,y,z
• 8 years agoHelpfull: Yes(0) No(0)
• first we compare the sequence....
  j,k,l,m,n,o,p,q....we see leaving middle term sequence is given as j,l,n,p
  now a,b,c,d.e,f,g,h,i,j,k,l,m,n,o....leaving three terms we get the sequence....
  now for last z,y,x,w,v,u,t,s,r...see it in reverse order,,,leaving one term we get the sequence...so ans is rur
  
• 8 years agoHelpfull: Yes(0) No(0)
• Answer is RUR
  J,L,N,P,(R) (taking alphabet by leaving 1 alpha)
  A,E,I,O,(U) (vowels order)
  Z,X,V,T,(R) (by starting from last alpha, leaving one).
  
• 8 years agoHelpfull: Yes(0) No(0)
• RUR
  because all first leters will become letter+1 nd next letter fist two letters will add 2 2 5 5 nd last letter will be letter -1
• 8 years agoHelpfull: Yes(0) No(0)
• option a is correct
• 6 years agoHelpfull: Yes(0) No(0)
• number all the alphabet you will get JAZ as 10126
  LEX as 12524
  hence 1st two digits are increasing by 2.in last two digits are decreasing by two and the middle digit is increasing by 4 hence in this way you will get NIV=14922 .Next you will find POT=161520 the middle digit is increased by 4+2 hence next you will get 182118 which is equal to RUR
  hence option A is correct
• 6 years agoHelpfull: Yes(0) No(0)
• A. RUR is the answer because J-L-N-P-R all have same interval in Increment order,U because of A-E-I-O-U are vowel and Z-X-V-T-R are in same order but in decereasing order.
• 6 years agoHelpfull: Yes(0) No(0)
• (j+1=L ),(A+3=E),(Z-1=X) = (JAZ to LEX)
  (L+1=N),(E+4=I),(x-1=V) = (LEX to NIV)
  (N+1=P),(I+5=O),(V-1=T )= (NIV to POT)
  (P+1=R),(O+6=U),(T-1=R) = (POT to RUR)
  option (a) is correct.
• 4 years agoHelpfull: Yes(0) No(0)
• 1st letter increases by 2
  J+2=L, L+2=N,N+2=P, P+2=R
  2nd letter increases by 4 for 1st 2 words, nd inc by 6 for next 2 words
  A+4=E, E+4=I,I+6=O, O+6=U
  3rd letter decreases by 2
  Z-2=X, X-2=V, V-2=T, T-2=R
  So the next word is RUR
  
  Ans: 1) RUR
• 4 years agoHelpfull: Yes(0) No(0)