Find the remainder when 987987....(upto 123 digits) is divided by 1001?

a)1
b)14
c)427
d)987

• d)987
  
  987987....(upto 123 digits) / 1001
  
  987987 / 1001 = 987 i.e, 6 digits are divisible by 1001
  
  so, when 987987....(upto 123 digits) is divided by 1001
  120 digits will be divisible & last 3 digit give the remainder 987.
• 10 years agoHelpfull: Yes(94) No(0)
• ans: d
  987987/1001(for 6 digits) remainder is zero,
  similarly 987987987987(for 12 digits ) remainder is zero
  hence upto 120 digits remainder will be zero
  therefore remaing last 3 digits of the number willbe the remainder i,e 987
• 10 years agoHelpfull: Yes(15) No(1)
• Note: Every value in the form of 'abcabc' is always divisible by 1001.
  here we have value 987987...upto 123 digits
  therefor 987987...upto 120 digits is divisible by 1001.
  hence the reaminder is 987.
• 10 years agoHelpfull: Yes(8) No(0)
• Ans will be 987
  but this qeus. from www.scoreph.com
• 10 years agoHelpfull: Yes(2) No(0)
• 
  Last 4 digits are. 7987
  7987/1001= 980
• 10 years agoHelpfull: Yes(1) No(5)
• Rakesh you are totally correct...
• 10 years agoHelpfull: Yes(1) No(0)
• what does 2^(n-1) gives
  
• 10 years agoHelpfull: Yes(0) No(0)
• RAKESH CAN YOU PLZ EXPLAIN THIS STEP BY STEP
  
• 8 years agoHelpfull: Yes(0) No(0)
• For every 6 iteration of divisions we get remainder 0. considering 123/6 we get 987 as remainder
• 7 years agoHelpfull: Yes(0) No(0)