number 81A84B6c,where each of the letters A,B,C respresents a distinct digits,is divisible by each of the 5,8,9.Find the value of A+B?

a)6
b)8
c)10
d)9

• d) 9
  
  81A84B6c is divisible by each of the 5,8,9.
  c can be 0/5
  
  B6c should be divisible by 8 so c can't be 5 => c = 0
  
  8+1+A+8+4+B+6+c should be multiple of 9
  => 27+(A+B) should be multiple of 9
  => (A+B)= 9
• 10 years agoHelpfull: Yes(76) No(1)
• 9 will be the answer,
  in order to divide 81A84B6C by 5 last digit i.e C should be 5 or 0
  but if we put as C=5 then number can't be divided by 8, so C will be 0
  for divide number by 9 sum of number should be the multiple of 9 here
  8+1+A+8+4+B+6+0=27+A+B
  27 is the multiple of 9.
  from option we see that none other then 9 are the multiple of 9
  so answer should be 9
• 10 years agoHelpfull: Yes(16) No(0)
• Ans.9
  For divisibility by 5..C must be 0 or 5.
  For divisibility by 8..B6C must be divisible by 8.
  For divisibility by 9..sum of all digits must be divisible by 9.
  Here..A=4,B=5 & C=0.
• 10 years agoHelpfull: Yes(4) No(0)
• c must be 5 or 0.... (27+a+b+c)/9 derfore if c=5...a+b must be 4 0r 13 0r 22 but they are no such options...so c=0..then (27+a+b)/9 a+b must be multiple of 9...so ans is 9
• 10 years agoHelpfull: Yes(1) No(0)
• 9
  
  sum of 8+1+a+8+4+b+6+c / 9=0
  27+a+b/9=0
  so a+b must be 9
• 10 years agoHelpfull: Yes(1) No(0)
• ans=9,
  first 81A84B6C is divisible by 9 so 8+1+A+8+4+B+6+C must be divisible by 9
  and is also divisible by 5 so C must be either 0 or 1
  con 1) if c=5 the above number is not divisible by 9
  con2) if c=5 the above no is divisible by 9 for A+B=9
  so ans is 9
• 10 years agoHelpfull: Yes(1) No(0)
• ans is 9 (d)
  
• 9 years agoHelpfull: Yes(1) No(0)
• A= 7; B=2; c=0
  c should be ----0
  Bcoz 5 is divisible by no ends with 0 or 5
  Last three digits must be divisible by 8 and 9
  i.e.,720
  A+B=9
• 10 years agoHelpfull: Yes(0) No(0)
• Rakesh you are right...
• 10 years agoHelpfull: Yes(0) No(0)
• c=0/5...but c=0,because if we take c=5 then it will not devive by 8.so c=0
  value of b=1/3/5/7/9 because last 3 digit should be divisible by 8.then
  value of a=8/6/4/2/0...because for the divisibility of 9... the addition of whole digit should be divisible by 9...so a+b=9...
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• 6 bcoz c is always zero becoz ccan't be 5 and only 0or 5 is divisibl by 5 and for division of 9 total should be divisible of 9
• 8 years agoHelpfull: Yes(0) No(0)