A dog takes 4 leaps for every 5 leaps of hare but 3 leaps of dog is equal to 4 leaps of hare compare speed?

Ans is 16:15 ...how

• Let the distance covered by dog in 1 leap is x and hare covered 1 leap is y.
  then, 3x = 4y
  => x =(4/3) y
  => 4x =(16/3) y
  
  Then, The ratio of speeds of dog and hare = Ratio of distances covered by them in the same time
  = 4x : 5y
  = (16/3)y : 5y
  =(16/3) : 5
  = 16:15
  Ans=16:15
• 10 years agoHelpfull: Yes(47) No(0)
• May be this shortcut works for you...
  actual speed of A:B
  
  given speed of A given speed of B
  ----------------------------------- :---------------------
  no.of steps of A in terms of length no.of steps of B in terms of length.
  
  dog:hare=(4/3):(5/4)=16:15
• 10 years agoHelpfull: Yes(19) No(0)
• 4:5 :: 3:4 so if u know ratio and proportion this equlas 4*4/5*3=16/15
• 10 years agoHelpfull: Yes(3) No(0)
• let the distance covered in 1 leap of dog be x meters
  let the distance covered in 1 leap of hare be y meters.
  it is given that 3 leaps of dog is equal to 4 leaps of hare.
  so, 3x=4y
  y=(3/4)x ------(1)
  for a period of time, say t seconds, it is given that dog takes 4 leaps for every 5 leaps of hare.
  speed of hare= dist/time = 5y/t m/sec
  speed of dog= dist/time = 4x/t m/sec
  
  ratio of their speeds= speed of dog/speed of hare
  = 4x/5y
  = 4x/15x/4 ---------(from (1) substituting y=(3/4)x)
  = 16/15
• 10 years agoHelpfull: Yes(2) No(0)
• In the point of time
  4x=5y------1
  In the point of distance 3:4
  3x=4y. =>. x=4y/3. => 4x=16y/3
  Speed of dog to hare using eq1
  4x=5y then 16y/3=5y. =16:15
• 10 years agoHelpfull: Yes(1) No(0)
• 4/5*4/3=16/15
• 10 years agoHelpfull: Yes(0) No(1)
• speed of dog=3/4;
  speed of hare=4/5;
  relative speed=(3/4)/(4/5)=15:16
• 10 years agoHelpfull: Yes(0) No(3)