The sum of a number and its square is 1406. What is the number?
1) 38
2) 39
3) 37
4) 29
5) None of these

• x + x^2 = 1406
  x^2+x-1406 = 0
  x = -1+-sqrt(1-4*1406)/2
  x = -1+-75/2
  x=-38 or x=37
  
  Ans : 3)37
• 10 years agoHelpfull: Yes(27) No(3)
• 7*7=49
  so 9+7=6 so solve this one to get the answer
  so c is the answer
• 10 years agoHelpfull: Yes(19) No(3)
• 3) 37
  let no. be x then
  
  x + x^2 = 1406
  => x^2 + x -1406 = 0
  => (x+38)(x-37) = 0
  => x = 37, -38
• 10 years agoHelpfull: Yes(11) No(1)
• 37+(37)2=1406.
  ans :3
  
• 10 years agoHelpfull: Yes(5) No(0)
• we will check using the unit digt.
  7*7= 9
  9+7= 6
  ans- 3
• 10 years agoHelpfull: Yes(5) No(0)
• X^2+X=1406
  
  X(X+1)=1406
  
  37*38=1406
• 10 years agoHelpfull: Yes(2) No(0)
• last digit of 37^2=9 add 37=last digit 6
  
• 10 years agoHelpfull: Yes(1) No(0)
• ans is 37
  
  let x is the no
  so x+x^2=1406
  37+37^2
  =37(37+1)
  =37*38
  =1406
• 10 years agoHelpfull: Yes(1) No(0)
• x+x^2=1406 solving this eqn we get x=37.
• 10 years agoHelpfull: Yes(1) No(0)
• x+x^2=1406
  last digit 7^2=9 & 9+7=6
  so 37
• 10 years agoHelpfull: Yes(1) No(0)
• 37 satisfies the problem
• 10 years agoHelpfull: Yes(1) No(0)
• 5
  no one match
• 10 years agoHelpfull: Yes(1) No(0)
• x^2+x=1406
  x+1=1406/x
  put the option and check
  option 3 will satisfy
• 10 years agoHelpfull: Yes(1) No(0)
• Ans is 37.
• 10 years agoHelpfull: Yes(1) No(0)
• x+x^2=1406
  x+x^2-1406=0
  (x+38)(x-38)=0
  x= -38 and 37
  ans= 37 i.e. option 3
• 10 years agoHelpfull: Yes(0) No(0)
• Better way,take x common,x(x+1),now check ,38*39,not possible,as 8*9 leaves remainder 2,similarly only 8*7 does,therefore multiply it and check it
• 10 years agoHelpfull: Yes(0) No(0)
• x^2+x=1406
  x^2+x-1406=0
  x^2+38x-37x-1406=0
  x(x+38)-37(x+38)=0
  x=-38 ,x=37
  
  so ans is option 3 38X37=1406
• 10 years agoHelpfull: Yes(0) No(0)
• 1406
• 10 years agoHelpfull: Yes(0) No(0)
• Answer is 37.
  Reason:
  last digit of 1406 is 6, which is not possible with 38(38^2 will have last digit 4 + 38 which gives last digit 2) or 39 or 29.
  Only 37^2+37 gives 9+7=6 as last digit
• 10 years agoHelpfull: Yes(0) No(0)
• squar digit 9 + 7=6 , so 37
  
• 10 years agoHelpfull: Yes(0) No(0)
• Ans 3) 37
  37*37+37=1406
• 10 years agoHelpfull: Yes(0) No(0)
• ans:3
  x2+x-1406=0;
  x=37
• 10 years agoHelpfull: Yes(0) No(1)
• short a
  1406 last digit 6
  6 should be number's square's last digit + number
  possible with only number having last digit as 7
  we have that
• 10 years agoHelpfull: Yes(0) No(0)
• answer is 37, by solving using quadratic equation we get the answer as 37
  
• 10 years agoHelpfull: Yes(0) No(0)
• opt 5)is the ans
• 10 years agoHelpfull: Yes(0) No(0)
• 37...37satisfies the question
  
• 10 years agoHelpfull: Yes(0) No(0)
• 7^2+7 gets last digit as 6 so ans is 37
• 10 years agoHelpfull: Yes(0) No(0)
• 3) 37
  let no. be x then
  
  x + x^2 = 1406
  => x^2 + x -1406 = 0
  => (x+38)(x-37) = 0
  => x = 37, -38
  
• 10 years agoHelpfull: Yes(0) No(0)
• ans: (3) 37
  
  let no is =x
  acoording to qustion x+x^2= 1406
  => x^2+x-1406=0
  => x^2+38x-37x-1406=0
  => x(x+38)-37(x-37)=0
  => (x-37) (x+38)
  x=37, x= -38
  datsy x=37
• 9 years agoHelpfull: Yes(0) No(0)
• Sum of a number + its square is :
  Let assume the number x ->
  x + x^2 = 1406
  x^2 +x -1406 = 0
  x^2 + 38 x - 37 x +1406 = 0
  x(x+38) - 37(x+38) = 0
  (x-37)(x+38) = 0
  x =37 , x = -38
  so ,
  Ans : option (3) i.e 37
  
• 9 years agoHelpfull: Yes(0) No(0)
• x + x^2 = 1406
  => x^2 + x -1406 = 0
  => (x+38)(x-37) = 0
  => x = 37, -38
  
  number has to be +ve . so its 37
• 9 years agoHelpfull: Yes(0) No(0)
• better way is to just take x common
  x(x+1)
  and check unit place by checking multiplication of unit places
  for 37
  7*8 this only giving unit place as 6.
• 9 years agoHelpfull: Yes(0) No(0)
• 37square +37=1406
• 6 years agoHelpfull: Yes(0) No(0)
• (37)^2+37=1406
• 6 years agoHelpfull: Yes(0) No(0)
• 5 it does not satisfy any of the above mentioned option.
• 6 years agoHelpfull: Yes(0) No(0)