Which of the following numbers are completely divisible by 11?
A. 3245682
B. 283712
C. 438416
D. 36894
1) Only A
2) Only B
3) Only C
4) Only D
5) All are divisible

• all are divisible.....check as if (sum of odd place digit-sum of even place digit)you will get either 0 or 11.hence all number is divisible by 11
  
• 9 years agoHelpfull: Yes(31) No(3)
• For a no. to be divisible by 11, diff. of sum of digits at odd places nd sum of digits at even places should be divisible by 11...
  In the given options , Only B satisfies the condition...
  283712 => (2+7+8) - (1+3+2) => 17-6 = 11
  
  Ans : 2) Only B
• 9 years agoHelpfull: Yes(9) No(23)
• all are divisible by 11,because diff of sum of digits at odd place nd sum of digits at even digit is 0 or divisible by 11
• 9 years agoHelpfull: Yes(5) No(2)
• option 5
  because when the difference of sum of odd position number and even position number is divisible by 11 then the number is completely divisible by 11.
• 9 years agoHelpfull: Yes(4) No(2)
• all are divisible
  
• 9 years agoHelpfull: Yes(2) No(1)
• Divisibility By 11 : A number is divisible by 11, if the difference of the sum of its
  digits at odd places and the sum of its digits at even places, is either 0 or a number
  divisible by 11.
  Ex. The number 283712 is divisible by 11, since :
  (sum of digits at odd places) - (sum of digits at even places)
  = (8+ 7 + 2)-(2+ 3 +1) = 11, which is divisible by 11.
  Answer: B)283712
• 9 years agoHelpfull: Yes(2) No(3)
• 3245682/11=29562
  283712/11=2579
  438416/11=3985
  36894/11=3354
  so ans is 5
• 9 years agoHelpfull: Yes(2) No(1)
• diff. of sum of digits at odd places nd sum of digits at even places are either 0 or multiple of 11 so in this case we have 0 & 11 option 5 is true
• 9 years agoHelpfull: Yes(1) No(2)
• 3
  Sum of odd placed digit-sum of even placed digit should be divisible by 11.
  4+8+1=13
  3+4+6=13
  13-13=0
  hence it i divisible by11
  
• 9 years agoHelpfull: Yes(1) No(0)
• a no. is divisible by 11 if the difference of sum of digit at odd places and sum of digits at even places is either 0 or 11.
  ans- 5
• 9 years agoHelpfull: Yes(1) No(0)
• only B
  because add odddigit- addevendigit that number is divisible by 11 means that's the answer
• 9 years agoHelpfull: Yes(1) No(0)
• (5) all are divisible
  
  RULE: add up all the digits in odd position of the number then add up all the digits in the even no.- If the difference of these two additions are 11 or 0 it means the no. is divisible by 11 else not.
  
  (3+4+6+2)-(2+5+8)=0
  (8+7+2)-(2+3+1)=11 (if the digits in even place is greater so we subtract the position of even place by position of odd place)
  (4+8+1)-(3+4+6)=0
  (3+8+4)-(6+9)=0
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• If you sum every second digit and then subtract all other digits and the answer is: 0, or, divisible by 11
  Answer:
  2)only B
  
• 9 years agoHelpfull: Yes(0) No(2)
• ALL ARE DIVISIBLE BY 11
  
• 9 years agoHelpfull: Yes(0) No(1)
• all devisible by 11
• 9 years agoHelpfull: Yes(0) No(0)
• All are divisible. Option D.
• 9 years agoHelpfull: Yes(0) No(0)
• all r divisible
  option 5
  diff between sum of all odd and even places are zero or divisible by 11
• 9 years agoHelpfull: Yes(0) No(0)
• 1
  
  sum of odd place digits-sum of even place digits=0
• 9 years agoHelpfull: Yes(0) No(0)
• All are divisible.if sum of odd and even place digit is subtracted,and if it gives either 0 or 11.that is why all are divisible.
• 9 years agoHelpfull: Yes(0) No(0)
• in given no 1st we have to check the difference of its( even place digit sum-odd place digit sum=0 0r 11then we can cay no is divisible by 11.
• 9 years agoHelpfull: Yes(0) No(0)
• 5) is right answer because difference of sum of digits in odd places and sum of digits in even places is zero or divisible by 11
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is 5) All are divisible
  divisibility by 11 is confirmed if (sum of odd digits - sum of even digits) is either 0 or multiple of 11.
• 9 years agoHelpfull: Yes(0) No(0)
• In the given options , Only B satisfies the condition...
  283712 => (2+7+8) - (1+3+2) => 17-6 = 11
  ans :B
  
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is option 5)All are divisible
  Rule for Divisibility By 11:If the difference between the sum of its digits at odd places and the sum of its digits at even places is either 0 or a number divisible by 11.
  So, as per rule all the given numbers are divisible by 11
• 9 years agoHelpfull: Yes(0) No(0)
• divisibility test for 11 is (sum of even digit)-(sum of the odd digit)
  equal to 11 or 0,here all value get 0 or 11
  so ans is all are divisible
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• only b because eventerm-oddterm
• 9 years agoHelpfull: Yes(0) No(0)
• 5,all r divisible
• 9 years agoHelpfull: Yes(0) No(0)
• all number are divisible by 11...check(sum of odd place)-(sum of even place)=ans
  if ans is divisible by 11 then it divisible number and ans=0 then its true
  
• 9 years agoHelpfull: Yes(0) No(0)
• Ans is 5) because the difference between the sum of its digits at odd places and the sum of its at even places is either 0 or a number divisible by 11
  so all the given numbers are divisible by 11
  
• 9 years agoHelpfull: Yes(0) No(0)
• option 5) is the right answer.
  The divisiblility check for 11 is to subtract the sum of numbers obtained in odd and even places since all numbers satisy the criterion all are divisible.
• 9 years agoHelpfull: Yes(0) No(0)
• x+x^2=1406
  x^2+x-1406=0
  by solving this quadratic eqn we get x=37
• 9 years agoHelpfull: Yes(0) No(0)
• (sum of numbers at odd places)-(sum of numbers at even places) should be divisible by 11 so answer is (2+3+1)-(8+7+2)=11 which is divisible by 11
  only b
• 9 years agoHelpfull: Yes(0) No(0)
• odd no-even no= 11 or 0 we get the answer
  
• 9 years agoHelpfull: Yes(0) No(0)
• 2
  (8+7+2)-(2+3+1)=11
  11/11
  it divisible by 11
• 9 years agoHelpfull: Yes(0) No(0)
• ans:5;all are divisible
• 9 years agoHelpfull: Yes(0) No(0)
• take the alternate number add them..we get two groups subtract that groups..if it is div then it will..
  
• 9 years agoHelpfull: Yes(0) No(1)
• all are divisible.....check as if (sum of odd place digit-sum of even place digit)you will get either 0 or 11.hence all number is divisible by 11(if any daught then calculator pe kr k dekh lo)
• 9 years agoHelpfull: Yes(0) No(0)
• all are divisible
  
• 9 years agoHelpfull: Yes(0) No(0)
• option is the correct
  
• 9 years agoHelpfull: Yes(0) No(0)
• ALL ARE DIVISIBLE SINCE WE GET THE DIFFERENCE OF SUM OF ODD PLACE AND EVEN PLACE AS 0(IN OPTION A,C,D) AND 11(IN OPTION B AS 2+7+8=17(ODD) AND 1+3+2=6(EVEN)
  SO 17-6=11)
• 9 years agoHelpfull: Yes(0) No(1)
• All r divisible
• 9 years agoHelpfull: Yes(0) No(0)
• all are divisible by 11 so its 5
  
• 9 years agoHelpfull: Yes(0) No(0)
• (2+7+8)-(1+3+2)=11
• 8 years agoHelpfull: Yes(0) No(1)