find the 28383rd term of the series 1234567891011121314...
need the explanation ..

• 28383rd term will be 3
  
  There are 9 numbers starting from 1 to 9. It means we have 9 digits.
  Number of digits from number 10 to 99 are 90*2=180 digits.
  Number of digits from number 100 to 999 are = 900*3=2700 digits
  
  Total number of digits from number 1 to 999 are = 9+180+2700 = 2889 digits
  
  Therefore remaining number of digits are = 28383-2889=25494 digits
  
  Now, we move on to 4 digits numbers starting from 1000 to 9999.
  Number of digits will be=9000*4=36000
  
  It means the 28383rd digit will lies between 4 digits numbers.
  
  number of 4 digits terms in (28383-2889)=25494 digits are = 25494/4= 6373 complete digits and 2 digits also(bcoz 6373 will be quitent and 2 will be remainder)
  
  6374 number will be 7373
  It means 3 will be the 28383rd number.
• 10 years agoHelpfull: Yes(2) No(0)
• number 6374 lies between 1000 .........9999
  
  using A.P we can find out it easily.
  
  An=a+(n-1)d
  = 1000+(6374-1)1
  = 1000+6373
  =7373
• 10 years agoHelpfull: Yes(1) No(0)
• cannot be found readily if the sequence is 1,2,3,4,5,6,7,8,9,1,0,1,1,1,2,...
  but, if the seq is 1,2,3,4,5,6,7,8,9,10,11,12,...
  then it is in A.P ans the 28383rd term will be 1+28382=28383.
• 10 years agoHelpfull: Yes(0) No(1)
• @sudhir
  
  how to know that 6374 term will be 7373
• 10 years agoHelpfull: Yes(0) No(0)