a 4 digit number is formed using the digits 0,2,4,6,8 without repeating.what is the sum of all possible numbers?

• (4-1)!*(0+2+4+6+8)*(11111)=1333320
• 10 years agoHelpfull: Yes(0) No(1)
• 4c1*4c1*3c1*2c1=4*4*3*2=96 possibles
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• kanika the method u gave is for all possible combinations using all the digits .....its nt the correct answer.
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• (4-1)*(1111)*(0+2+4+6+8)
  =6666*20=133320 ans
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• 0, 2, 4, 6, 8
  1st place posibility = 4C1
  2nd place posibility = 4C1
  3rd place posibility = 3C1
  4th place possibility = 2C1
  
  then 4C1*4C1*3C1*2C1 = 96 Answer
• 9 years agoHelpfull: Yes(0) No(0)