A wire is looped in the form of a circle of radius 28 cm It is bent again into a

Perimeter of Circle=Perimeter of square as made from same ware..
so perimeter of square=2*22*28/7=176
so length of square=176/4=44.
length of diagonal=44*root(2).
10 years agoHelpfull: Yes(38) No(3)

circumference of circle= 2*(pi)*r= 2*28*22/7=176
perimeter of square = 4*a=174
=>a=176/4=44
diagonal= a* root(2)=44*1.41=62.04
10 years agoHelpfull: Yes(10) No(3)
was this relly asked in elitmus ?? o.O
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perimeter of circle=perimeter of square
one side of square= (2*22*28)/(7*4)=44
diagonal of square=44*1.414cm
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circumference of circle= 2*(pi)*r= 2*22/7*28=176
perimeter of square = 4*a=174
=>a=176/4=44
diagonal= a* root(2)=44*1.414=62.04
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22/7*28*28=.5*diag*diag;
so,diag=70.11cm.
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2*(22/7)*28=circum of circ=X(say)
4a=X;
a=X/4;
ans is (2^1/2)*a
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perimeter of circle=2pi*r=2*28*22/7=176cm
perimeter of square=176=4a
a=44cm
the max possible digonal=a*1.414=62.216cm
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ans
62.216
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A wire is looped in the form of a circle of radius 28 cm.It is bent again into a square form .What will be the length of the diagonal of the largest square possible thus?