The base of a pyramid is a rectangle of sides 18m*26 m and its slant height to the shorter side of base is 24 m.find its volume.

• formula for volume of a Pyramid with rectangular base: LWH/3
  l-length, w-width, h-height
  h=20.174(by pythagoras theorem)
  volume=26*18*20.174 / 3
  =3147.18 cubic mtr
• 10 years agoHelpfull: Yes(11) No(1)
• ans=3147.18 m^3
  volume of pyramid=l*w*h/3=18*26*20.17/3=3147.18 m^3
  here as per ques
  h=(24^2-13^2)^1/2
  =20.17m
• 10 years agoHelpfull: Yes(4) No(2)
• h=(24^2-9^2)^1/2(a/c to pythagoras theorem because its slant height to the shorter
  side of base hence shorter side is 18).
  volume=18*26*h/3
• 10 years agoHelpfull: Yes(1) No(0)
• Y the base side is choosen 26 side for calculating the height. Given in que that the slant height to the shortest side of base is 24. So we have to choose 18.. Please correct me if I am getting it wrong.
• 9 years agoHelpfull: Yes(1) No(0)
• area of pyramid=1/3*height*area of base;
  so,area=1/3*height*(26*18);
  nd height*height=24*24-13*13;(pythgorous,base of triangle=26/2=13)
  so area=3147.1
• 10 years agoHelpfull: Yes(0) No(6)
• height=sqrt(24^2-13^2)=20.17m
  volume=(26*18*20.17)/3m63
• 10 years agoHelpfull: Yes(0) No(0)