If "segment" is coded as "rffndou", then "ritual" is coded as what?? Please give the explanation

• SEGMENT => RFFNDOU
  S-1 = R
  E+1 = F
  G-1 = F
  M+1 = N
  E-1 = D
  N+1 = O
  T+1 = U [I think it might be S instead of U]
  
  RITUAL
  R-1 = Q
  I+1 = J
  T-1 = S
  U+1 = V
  A-1 = Z
  L+1 = M
  
  Ans : QJSVZM
  
• 9 years agoHelpfull: Yes(54) No(2)
• s-1=r;
  e+1=f;
  g-1=f;
  m+1=n;
  e-1=d;
  n+1=o;
  t-1=s;(question may wrong)
  so for ritual,
  r-1=q;
  i+1=j;
  t-1=s;
  u+1=v;
  a-1=z;
  l+1=m;
  so,
  ans is qjsvzm
  
• 9 years agoHelpfull: Yes(4) No(2)
• ans is qjsvzm
• 9 years agoHelpfull: Yes(2) No(1)
• qjsvbm
  
  
  as s comes after t
  e comes before f
  g comes after f
  m comes before n
  e comes after d
  n comes before o here
  t also comes before u.
  so rffndou can be coded as "qjsvbm"
  
• 9 years agoHelpfull: Yes(1) No(1)
• S E G M E N T
  -1 1 -1 1 -1 1 -1
  R F F N D O U
  THEN
  R I T U A L
  -1 1 -1 1-1 1
  Q J S V Z M
• 9 years agoHelpfull: Yes(1) No(0)
• in this coding one one char later and one char before is written so the answer will be =qjsvzm
• 9 years agoHelpfull: Yes(1) No(0)
• Segment has been coded as rffndou. r comes before s; f comes after e; f comes before g; n comes after m; d comes before e; o comes after n; u comes after t. Similarly following the same pattern, ritual can be coded as qjsvbk
• 9 years agoHelpfull: Yes(0) No(1)
• QJSVZM
  
  SJ
  GV
  EM
  T
• 9 years agoHelpfull: Yes(0) No(0)
• the ans is qjsvzm..the first letter "r" is replaced by the the previous letter...the next letter "i" is replaced by the next letter and so on.
• 9 years agoHelpfull: Yes(0) No(0)
• if after word=+1 ,before word =-1 .then u find similarity and ans=qjsvzm
• 9 years agoHelpfull: Yes(0) No(0)
• gjsvzm.. in even place albhbets r increasing bt in odd places they replaced from decreasing character
• 9 years agoHelpfull: Yes(0) No(0)
• ans is
  QJSVZM
• 9 years agoHelpfull: Yes(0) No(0)
• ritual - qjsvzm
• 9 years agoHelpfull: Yes(0) No(0)
• qjstbk
  in segment
  's' before alphabet 'r'
  'e' after alphabet 'f'
  letters go like this
  and for ritual ans is
  qjstbk
• 9 years agoHelpfull: Yes(0) No(0)
• And:qjsvzm
  Reason:-1 and +1
• 9 years agoHelpfull: Yes(0) No(0)
• do +1 to the 1st letter nd -1 to the 2nd ietter and so on...
  so that result is
  qjsvzm
• 9 years agoHelpfull: Yes(0) No(0)
• For alternate letters add 1 and subtract 1 so answer is qjsvzm
• 9 years agoHelpfull: Yes(0) No(0)
• qjsvzn.alternative prefix and suffix
• 9 years agoHelpfull: Yes(0) No(0)
• answer is qjsvbm becoz in the segment the code is decrement/increment 1 respectively,coming to last two letters in segment like n,t are incremented so thats why answre is: qjsvbm
• 9 years agoHelpfull: Yes(0) No(0)
• QJSVZM
  S-1 = R
  E+1 = F
  G-1 = F
  M+1 = N
  E-1 = D
  N+1 = O
  T+1 = U
  Similarly we can get the ans for other by doing the same procedure
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• qjsvzm
  it is alternately coded to be preceding and succeeding leters
• 9 years agoHelpfull: Yes(0) No(0)
• yo man ram yo.
• 9 years agoHelpfull: Yes(0) No(0)
• RITUAL=QJSVZM
• 9 years agoHelpfull: Yes(0) No(0)
• qjsvzm as characters are decreasing first then increasing
• 9 years agoHelpfull: Yes(0) No(0)
• The sequence is as follows:
  The first letter is coded by the preceding alphabet and the next one as the successor alphabet. example s preceded by e and e succeeded by f,g preceded by f and m succeeded by n.
  Solution: qjsvzm
• 9 years agoHelpfull: Yes(0) No(0)
• qjsvzm -1 +1 -1 +1 -1 +1
• 9 years agoHelpfull: Yes(0) No(0)
• "qjsvzm" would be the code
• 9 years agoHelpfull: Yes(0) No(0)
• qjsvzm is ans
• 9 years agoHelpfull: Yes(0) No(0)
• We use the just previous and just after alphabets alternatively..For the first case the previous alphabet of 's' is 'r',then the alphabet next to 'e' is 'f'.And so on.So the answer of 'ritual' is 'qjsvzm'
• 8 years agoHelpfull: Yes(0) No(0)
• "ritual " is coded as "qjsvzk" each letter which is an odd position , write its code is one letter less than current letter and each letter which is an even position , write its code is one letter more than current letter .
• 8 years agoHelpfull: Yes(0) No(0)
• The segment is coded as follows
  S=before alphabet of s i.e, r
  e=after alphabet of e i.e., f
  g=before the alphabet of g i.e., f
  m=after letter of n i.e., n
  and so on.
  Similarly, the word ritual is coded as fqjsvzm.
• 8 years agoHelpfull: Yes(0) No(0)
• r-1=q
  i+1=j
  like that the test follows
  so final ans is qjsvzm
• 8 years agoHelpfull: Yes(0) No(0)
• qjsvzm
  odd position are being the just pervious letters and at even position next letter as in english alphabet
• 8 years agoHelpfull: Yes(0) No(0)
• qjsvzm because alternately one is next letter an another is before letter
• 8 years agoHelpfull: Yes(0) No(0)
• SEGMENT
  RFFNDOU
  
  the pattern is like
  S-1= R
  E+1= F
  G-1= F
  M+1= N
  E-1= D
  N+1= O
  T+1= U
  
  looking at the last two words their code letters are +1 meaning their coded letters are successors og them
  
  similarly RITUAL
  R-1= Q
  I+1= J
  T-1= S
  U+1= V
  A-1= Z
  L-1= K
  here on doing so the second last is -1 so the last will be also the same .
  therefore the answer is QJSVZK
  
• 8 years agoHelpfull: Yes(0) No(0)
• -1 then +1 ans;-qjsvzm
• 7 years agoHelpfull: Yes(0) No(0)
• S E G M E N T values 19 5 7 13 5 14 20 and R F F N D O U values 18 6 6 14 4 15 21 it has the difference is 1.so answer is Q J S V Z M
• 5 years agoHelpfull: Yes(0) No(0)