A moves 4 km east from his starting point. He then travels 5 km north. From that point he moves 8
km to the east. How far is A from his starting point?
1] 13 km 2] 19 km 3] 5 km 4] 10 km

• 4+8= 12
  and 5
  
  so we have the base and the perpendicular
  now by P theorem H*H= 12*12+5*5 = 144+25 =169
  So, H = 13 ans.
• 10 years agoHelpfull: Yes(12) No(0)
• ans:13km
  
  4km east,5km north,8km east;;;;;;;;;;so totally 12km east,5km north
  
  therefore sqrt[(12*12)+(5*5)]=13km
  
• 10 years agoHelpfull: Yes(5) No(0)
• Ans:17km
  Add all the three distances.
• 10 years agoHelpfull: Yes(4) No(7)
• the ans is 13 bcz 4+8=12
  now it forms a 90* triangle so root(12^2+5^2)=13
• 10 years agoHelpfull: Yes(2) No(0)
• 13 km. he has effectively traveled 12 km East of his starting point and 5 Km North of it. using pythagoras theorum his total distance evaluates to 13km.
• 10 years agoHelpfull: Yes(2) No(0)
• ans is 12km...
• 10 years agoHelpfull: Yes(1) No(1)
• i think the answer is 11.403
• 10 years agoHelpfull: Yes(0) No(0)
• the answer is 5km
• 10 years agoHelpfull: Yes(0) No(1)
• 17 km is the answer
• 10 years agoHelpfull: Yes(0) No(0)
• plzzee explain..!!
• 10 years agoHelpfull: Yes(0) No(0)
• Please explain properly
• 10 years agoHelpfull: Yes(0) No(1)
• It's 13.09 km.
• 10 years agoHelpfull: Yes(0) No(2)
• 13
  4km from east and then 5 km north then east 8 km makes a triangle with base 12 and height 5 km so net distance is 13km by pythagoras theorem
• 10 years agoHelpfull: Yes(0) No(0)
• 13
  
  
  no explanation..
  
• 10 years agoHelpfull: Yes(0) No(0)
• 13
  4km east then 5km north ie vertical distance and theb 8km east
  so 4+8=12
• 10 years agoHelpfull: Yes(0) No(0)
• ans. 5km,by Pythagoras theorem.
• 10 years agoHelpfull: Yes(0) No(0)