CSC
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Numerical Ability
Pipes and Cistern
A person walking 5/6 of his usual rate is 40 minutes late. What is
his usual time?
Read Solution (Total 3)
-
- Let t be the usual time. If the usual rate is 1 unit, then the unusual rate is 5/6.
Balance by the distance,
1*t = (5/6)(t+40)
6t = 5(t+40)
Solve for t,
t = 200 minutes = 3 hrs 20 min - 11 years agoHelpfull: Yes(21) No(4)
- Answer 200min
Let the actual speed of the man is S and actual time is t
Now the Speed is 5/6S and it takes t+40 minutes
As the distance is same
S*T=5/6S*(T+40)
solving this we get t=200 minutes
- 12 years agoHelpfull: Yes(18) No(4)
- we know that speed is inversely proportional to time
let 'ut' be usual time
so 6/5(ut)-ut=40
ut=200min that is 3 hr 20 min - 9 years agoHelpfull: Yes(2) No(0)
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