A train travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs.What is the distance traveled

A.) 210 kms
B.) 30 kms
C.) 60 kms
D.) 90 kms

• let the speed in the forward journey be x km/hr, also
  given time taken in fwd journey = 7 hrs
  
  during return journey
  
  speed=(x+12)km/hr
  time=5hrs
  
  nw distance travelled in both the cases is same therefore
  
  forward journey distance=return journey distance
  
  7x=5(x+12)
  7x-5x=60
  2x=60
  x=30km/hr
  
  therefore distance travelled= 30*7=210km
  
  or =5*(30+12)=210km
• 12 years agoHelpfull: Yes(9) No(1)
• Let the speed of the car be x
  According to the formula given below we substitue
  
  distance = speed * time
  Distance travelled in the forward journey=7*x----(1)
  Distance travelled in the reverse journey=5(x+12)=>5x+60.(2)
  
  now,
  
  7x-(5x+60)=0(=>7x gives the distance, 5x+60 also gives same distance )
  so wen we subtract both we get 0.
  7x-5x-60=0
  2x=60
  x=30--->which gives the speed of the forward journey.
  when we substitute in the first eq we get
  7*30=210km.
  
• 11 years agoHelpfull: Yes(1) No(0)