Z^2 = 100^2 - (X^2),
X from 0 to 100,
for how many values of X ,Z is divisible by 6.

• Ans ll be 0...
  z^2 = 100^2 - x^2
  z = sqrt (100^2 - x^2)
  z = sqrt(100+x)(100-x)
  z = sqrt(100+x) * sqrt(100-x)
  So check for all the Perfect square values which is >100 nd (100+x)=121 -> (100-x)=79 -> 11*sqrt(79) not divisible by 6
  x=44 -> (100+44)=144 -> (100-x)=56 -> 12*sqrt(56) not divisible by 6
  Like that check for all perfect square values... None ll be divisible by 6...
  So ans is 0
  
  Ans : 0
• 10 years agoHelpfull: Yes(45) No(17)
• ans is 3
  for x=28 z=96, x=80 z=60 , x=100 z=0
  
  i don't know the procedure to solve the question. i had made program for this in c++ adn got the ans from there.
• 10 years agoHelpfull: Yes(35) No(6)
• x values are 16 only...
  because Z always divided by 6 means Z always contains of 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96 so you can insert values of X between 0 to 100 only multiple of 6 but max 96 after that u get values are negative
• 10 years agoHelpfull: Yes(6) No(14)
• 3 values of x
• 10 years agoHelpfull: Yes(5) No(3)
• take different values of z as multiples of 6
  6^2=100^2-x^2
  x^2=100^2-6^2
  x^2=(100-6)(100+6)
  if the ans will be a perfect square then the ans will be the value of x for z to be divisible by 6
  following these steps we will have to check up to 16 factors of 6 i.e. 96 will be the last one and one of the right ans
  you will finally get the ans as 3 for the number of values of x for which z is divisible by 6
• 10 years agoHelpfull: Yes(5) No(4)
• z^2=100^2-x^2
  X^2=100^2-Z^2
  
  since, z is divisible by 6, it is a multiple of 6 also.
  
  so the values of Z^2 =0, 6^2, 12^2, 18^2, 24^2, ...........96^2
  for all these values, check for which value of Z^2 . X^2 is a perfect squares..
  
  after check we only get z=0, 60, 96... three values only.
• 10 years agoHelpfull: Yes(5) No(1)
• ans is 0
  for z=sqrt(100+x)*sqrt(100-x)
  x value 96 is possible but it gives z value 28 which is not divisible by 6.
  
• 10 years agoHelpfull: Yes(3) No(2)
• From 0 to 100.
  
  At x = 0 then z = 100
  x = 28 then z = 96
  x = 60 then z = 80
  x = 80 then z = 60
  x = 28 then z = 96
  x = 60 then z = 80
  x = 80 then z = 60
  x = 96 then z = 28
  x = 100 then z = 0
  
  Only 4 values of x are there in which Z is divisible by 6
  i.e.
  x = 28 then z = 96
  x = 60 then z = 80
  x = 80 then z = 60
  x = 100 then z = 0
  
  But According to my Program Logic
  
  for(int x = 0; x
• 10 years agoHelpfull: Yes(3) No(7)
• x can be 28 ,80;
  first take x=28.
  z^2=100^2 - 28^2
  =10000 - 784
  =9216
  so, z=sqrt(9216) =96 which is divisible by 6;
  
  now
  take x=80.
  z^2=100^2 - 80^2
  =10000 - 6400
  =3600
  so, z=sqrt(3600) =60 which is divisible by 6;
  
  so there will be two values for which Z is divisible by 6;
  
  
• 9 years agoHelpfull: Yes(3) No(0)
• x=8
  z^2=36
  z=6
  1 value
• 10 years agoHelpfull: Yes(2) No(1)
• z^2=(100+x)(100-x).as z shd be devisable by 6 means z62 must be devisable by 36.now the minumum value of (100-x) =0 and max of(100+x)=200.so we have to find how many numbers within 0 to 200 are devisable by 36.so the answer is 6
• 10 years agoHelpfull: Yes(2) No(0)
• 0
  
  check for these conditions
  z^2=(100-x)*(100+x)
  and u can check for the condition z^2+x^2=100^2
• 10 years agoHelpfull: Yes(1) No(1)
• z^2=100^2-x^2
  z^2=(100+x)(100-x)
  
  now Z^2 will be divisible by 6 if either of the 2 brackets will be divisible
  and range of 100+x will be upto 200
  range of 100-x will be upto 100
  so there will be 198/6=33 values of x which will cause z^2 to be divisible by 6.
• 10 years agoHelpfull: Yes(1) No(0)
• Ans wil be 5...
  z^2 = 100^2 - x^2
  z = sqrt (100^2 - x^2)
  z = sqrt(100+x)(100-x)
  z = sqrt(100+x) * sqrt(100-x)
  if(100+x)or(100-x)is multiple of 36 then it must be divide by 6
  when x=64,28,8,44,80,then it must be multiple of 36.
  
  Ans : 5
• 10 years agoHelpfull: Yes(1) No(3)
• x can be 28 ,80;
  first take x=28.
  z^2=100^2 - 28^2
  =10000 - 784
  =9216
  so, z=sqrt(9216) =96 which is divisible by 6;
  now
  take x=80.
  z^2=100^2 - 80^2
  =10000 - 6400
  =3600
  so, z=sqrt(3600) =60 which is divisible by 6;
  
• 8 years agoHelpfull: Yes(1) No(0)
• ONE VALUE 10
• 10 years agoHelpfull: Yes(0) No(4)
• Ans. is 1 value ie. 0
  
  for value of x=0 only z is divisible by 6.
• 10 years agoHelpfull: Yes(0) No(3)
• 3 Values of X if x>=0 && x
• 10 years agoHelpfull: Yes(0) No(1)
• ans will be 16
• 10 years agoHelpfull: Yes(0) No(1)
• what is the right solution guys ??plz explain also..
• 10 years agoHelpfull: Yes(0) No(0)
• Equation should be
  Z =100^2-x^2
  
  Not z^2
• 9 years agoHelpfull: Yes(0) No(0)
• EHTESHAM U R DAMN RIGHT...THANKS
• 9 years agoHelpfull: Yes(0) No(0)
• ans wil be 3.
  z^2 can be 16,36,96 whch are divisible by 6.
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 66 values
  33 for +ve nd 33 for -ve
• 8 years agoHelpfull: Yes(0) No(0)