The sum of the digit of two digit no is 11.if we interchange the digit ,then the new no found is 45 less than the original no.find the original no.

• x+y = 11
  original no. = 10y+x
  After interchanging digit
  new number = 10x+y
  so,
  10x+y = 10y+x -45
  9x - 9y = -45
  x-y = -5
  Now, 2x = 6
  x = 3
  y = x+5 = 3+5 = 8
  original no be 83
• 10 years agoHelpfull: Yes(12) No(1)
• x+y=11
  10y+x-10x-y=45
  so
  9y-9x=45
  or,y-x=5
  y=8
  x=3
  no=83
• 10 years agoHelpfull: Yes(1) No(0)
• 83 is d original no
  8+3=11 reverse it 38
  difference 83-38=45
• 10 years agoHelpfull: Yes(1) No(1)
• less than 45 so the number start with 3
  3+8=11
  38
• 10 years agoHelpfull: Yes(1) No(0)
• x+y=11
  10y+x=10x+y-45
  x=9
  y=3
  93
• 10 years agoHelpfull: Yes(0) No(8)
• ans -is 8, 3
• 10 years agoHelpfull: Yes(0) No(0)
• it will be 83
• 10 years agoHelpfull: Yes(0) No(0)
• given x+y=11
  let the no be 10x+y
  and after interchanging
  10y+x-45=10x+y
  so we get x=3 and y=8
  and no is 38
• 10 years agoHelpfull: Yes(0) No(4)