amar,akbar,antony are friends .When compare the weight of these members akbar is 80% less weight than amar and antony 15% less weight than amar. at that time they have seen Farah. All the members weight is 242kg. Farah weight is one-third of all their weight. find their weight and write in a descending order.
a) amar,akbar,antony,Farah
b) akbar,antony,Farah,amar.

• let amar =100,then antony =75,akbar =20 and farah =1/3(100+75+20)=65
  so,order in descending order is amar,antony,farah,akbar
  
• 10 years agoHelpfull: Yes(12) No(3)
• amar,anthony,farah,akbar
• 10 years agoHelpfull: Yes(1) No(0)
• akbar lighter than amar by 80% and antony is also lighter than amar but heavier than akbar.so in descending order of their weights, akbar,antony and amar. only b is satisfying
  
• 10 years agoHelpfull: Yes(1) No(2)
• akbar-amar=80
  antony-amar=15
  akbar+amar+antony+farah=242
  farah=1/3(akaar+amar+antony)
  from 1st 2 akbar+antony=95
  sub in 3rd equation both farah and akabr+antony
  then amar=-37
  akbar=53
  antony=-22
  farah=19.6
  decending order option a ia right
  
• 10 years agoHelpfull: Yes(0) No(2)