40 40 will end in how many zeroes 40 8 x 40 9 x 40 8 40

This is the method to calculate the trailing zeros in a factorial of a number:

To find trailing zeros in n!, we need to find (n/5) + (n/(5^2)) + (n/(5^3)) +... + (n/(5^x)
Where (5^x)
9 years agoHelpfull: Yes(16) No(3)
How many multiples of 5 are between 1 and 40?
5, 10, 15, 20, 25, 30, 35, 40
Plus one more because we have 5x5=25.
So, there are 9 trailing 0's on 40!
so, there will be 9*40! number of trailing 0 in 40!^40!
9 years agoHelpfull: Yes(12) No(3)
It would b 9*40!
9 years agoHelpfull: Yes(7) No(0)
40!/5+40/25=9
9*9*9*9......................................40!
so ans 9^40!
9 years agoHelpfull: Yes(5) No(2)
40/5^1 = 8

Hence 40!^40! ll end in 8^40!

Ans : 8^40!
9 years agoHelpfull: Yes(3) No(10)
40! contains (40/5)+(40/25)=8+1=9 zero
40!^40!=9*40! no of zeroes
9 years agoHelpfull: Yes(2) No(0)
40!/5=8
8^40^40! zeros
9 years agoHelpfull: Yes(1) No(7)
the answer will be 40/5+40/25^40!=9^40!
9 years agoHelpfull: Yes(1) No(0)
how can u divided by 5.means 40/5!..
any formula u applied for it
9 years agoHelpfull: Yes(1) No(1)
please tell me how 45/25 become 1
8 years agoHelpfull: Yes(1) No(1)
40! Will have 9 zero since there is two 5 in 25....then ...answer 8^40 should not be the answer
9 years agoHelpfull: Yes(0) No(0)
some 1 plz how 2 do this type of ques.
9 years agoHelpfull: Yes(0) No(0)
8^40... 40! contains 8 last digid then 40! is power
9 years agoHelpfull: Yes(0) No(1)
explain fully plz..
9 years agoHelpfull: Yes(0) No(0)

40!^40! will end in how many zeroes?
40!
8 x 40!
9 x 40!
8^40!