ABCD is a rectangle with AD being longer side.P and Q be the mid-points of AB and CD.x is a point on AD.Then what is the ratio of Area of PQCB to XCB?
a)DQ=PB
b)AP=CQ

• Area of rectangle formed by PQCB is PQ*CQ
  Area of triangle formed by XCB is (1/2)BC*AB
  Here PQ=BC=AD; XN=AB=CD;
  Finally the ratio becomes PQCB:XCB=1:1.
• 9 years agoHelpfull: Yes(14) No(0)
• Any one of the obtion will help us in solving the ques..
• 9 years agoHelpfull: Yes(9) No(2)
• neither of the statements help to get a solution...as they are already impliedap=pb=dq=cq as the fig is a rectangle.
• 9 years agoHelpfull: Yes(2) No(0)
• Neither as position of x is not clear with both the option
• 9 years agoHelpfull: Yes(1) No(0)
• ratio of Area of PQCB to XCB=1
• 9 years agoHelpfull: Yes(0) No(2)
• ratio will be one and option a is a trivial condition but option b is needed to solve the problem
• 9 years agoHelpfull: Yes(0) No(3)
• answer is 8
  possible combinations :
  1. papgpsbrmp
  2. papgprbsmp
  3. pgpapsbrmp
  4. pgpaprbsmp
  5. rbspapgpmp
  6. sbrpapgpmp
  7. rbspgpapmp
  8. sbrpgpapmp
• 9 years agoHelpfull: Yes(0) No(5)
• any option is sufficient because
  DQ=PB
  =>DQ/PB=1
  SIMILARLY
  AP/CQ=1
• 9 years agoHelpfull: Yes(0) No(0)
• both a & b is right
  
• 9 years agoHelpfull: Yes(0) No(0)
• in this question p ,q are the middle point through which the triangle pass and one perpendicular draw it than area of triangle is b*c/2 and rectangle b*c than devide and get the answer
• 9 years agoHelpfull: Yes(0) No(0)
• PQCB:XCB=1:1
  
• 8 years agoHelpfull: Yes(0) No(0)
• the ratio between PQCB : XCB= 1:1
• 8 years agoHelpfull: Yes(0) No(0)