Elitmus
Exam
Numerical Ability
Algebra
a2+ab+b2=259
b2+bc+c2=1299
c2+ac+a2=499
then a+b+c=?????
Read Solution (Total 4)
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- 26
put a2+ab+b2=(a3-b3)/(a-b) and add three terms - 10 years agoHelpfull: Yes(4) No(7)
- option plz...
- 10 years agoHelpfull: Yes(2) No(2)
- ans:38.5 make all terms as perfect squares
- 10 years agoHelpfull: Yes(2) No(4)
- Wrong Que..
a^2*b^2+a^2+b^2+1= (a^2+1)(b^2+1)
by using above one we can write
a^2*b^2+a^2+b^2+1=260..(1)
b^2*c^2+b^2+c^2+1=1300..(2)
c^2*a^2+c^2+a^2+1=500..(3)
by doing (1)/(2) we will get a^2+1/c^2+1 = 1/5..(4)
by doing (4)*(3) we will get (a^2+1)^2=10,
by solving a=3, b=5,c=7
so a+b+c=15 - 10 years agoHelpfull: Yes(0) No(3)
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