COIN-SNUB=COUNT

• sorry my last ans was wrong, write ans is
  
  COUNT-COIN=SNUB
  10652-1085=9567
• 10 years agoHelpfull: Yes(17) No(10)
• how would u get 5 digit number by subtracting two 4 digit number ??
• 10 years agoHelpfull: Yes(10) No(1)
• The correct ans is
  COUNT-COIN=SNUB
  10435-1093=9342
• 8 years agoHelpfull: Yes(3) No(2)
• c=1,s=9,n=5,u=6,i=8,b=7,n=5,t=2
  then,10652-1085=9567 ans
  subtraction is "upside-down" addition
  we can write ,
  S N U B
  + C O I N
  ------------------
  C O U N T in this form C=1 since it is the only carry-over possible from the sum of two single digit numbers
  then S=9 ,
  9+1=10,that means,S+C=O,soO=0 carry 1
  N+O=U & U+I=N
  1+U+I=N,1 IS CARRY, The possibility of u+i=(6,7),6,8.....something
  if u=6&i=8 sum of these no is 15,u+i=n that means i=5
  we check if n=5 then n+o=u,5+0=5 and take carry 1of 15.that means 1+5=6=u
  b+n=t,
  b=7 then b+n=t,7+5=12,t=2 carry 1
  after this we can put all collect no of digit
  10652-1085=9567
• 8 years agoHelpfull: Yes(3) No(0)
• plzz anyone explain this ans
• 10 years agoHelpfull: Yes(2) No(2)
• COUNT-COIN=SNUB..... 10425-1083=9342.
• 10 years agoHelpfull: Yes(1) No(7)
• actually question is COUNT-COIN=SNUB 10659-1086=9573
  
• 10 years agoHelpfull: Yes(1) No(7)
• as snub means means discarded but it would be no
  
• 9 years agoHelpfull: Yes(1) No(0)
• Actually the question should be
  COUNT-COIN=SNUB
• 10 years agoHelpfull: Yes(0) No(2)
• sorry question is coin+snub=count 9085+1567=10652
• 10 years agoHelpfull: Yes(0) No(0)
• count - coin= snub
  
  10653-1085=9562
• 9 years agoHelpfull: Yes(0) No(1)
• imran thumbs up
  
• 9 years agoHelpfull: Yes(0) No(0)
• Question is 100% wrong, though we take COUNT-COIN=SNUM, AS O =0, then how U-O =N.
• 9 years agoHelpfull: Yes(0) No(1)
• COUNT-COIN=SNUB
  10652-1085=9567
  C=1 O=0 U=6 N=5
  T=2 B=7 I=8
  
• 8 years agoHelpfull: Yes(0) No(0)
• @Panchhi Sahu
  it is not possible to assign 9 to Two different alphabets. So correct answer is
  
  COUNT-COIN=SNUB
  10652-1085=9567
• 8 years agoHelpfull: Yes(0) No(0)