12233344441122223333334……………………………………what is 2888th no in this sequence

• Ans:1
  1st term=1223334444=10
  2nd term=11222233333344444444=20
  3rd term=40
  it increase double=10 20 40 80 160 320 640 1280 2560
  .....9th term=2560
  in 9th term 1s coming 256 time,
  2s coming 512 time,
  3s coming 768 time,
  4s coming 1024 time,
  Total= 2560
  actual qustn is 2888th term
  in 10th term 1s coming 512 times
  =2560+338=2888 [336
• 9 years agoHelpfull: Yes(16) No(10)
• 3
  1223334444 has 10 numbers
  11222233333344444444 has 20 numbers.
  similarly 111222222333333333444444444444 has 30 next 40 and so on.
  In this way upto 23rd line we will have a total of 2760 numbers.10(n*n+1)/2
  2888-2760=128
  2761 is 1 and this is 24th line .
  in 24th line 1 repeats 24 times
  2 repeats 2*24=48 times.
  3 repeats 72 times.
  24+48 = 72 .. 128-72=56.
  so after the last 2 taking 56 steps is giving us 3.
  Hence the 2888 number is 3.
  
• 9 years agoHelpfull: Yes(9) No(3)
• answer is 2
  take the series 1st time 1 is coming 1,2-2,3-3,4-4=10
  2nd time 1-2,2-4,3-6,4-8=20
  3rd time it continious he total also it doubles 10+20+40+80+160+320+640+1280=2550
  9th time 1-192,2-382
  2550+192=2742 we need 2888 then definetly it s 2 because 2 comes 382 times
• 9 years agoHelpfull: Yes(6) No(7)
• sorry in the above 1=256
  and 2=512
  2550+256=2806
  2806+512=2880 will be in this so answer is 2
• 9 years agoHelpfull: Yes(6) No(2)
• Answer will be 1
• 9 years agoHelpfull: Yes(2) No(3)
• 1 is the answer
  
  the first 1 to 4 has 10 nos. next 1 to 4 has 20 nos. next 1 to 4 nos. would be 40nos.
  hence a G.P. is formed 10, 20, 40, .....
  the (2560 + 320)th no. will be 1
• 9 years agoHelpfull: Yes(2) No(4)
• answer is 2.
  the series ends with 4, whose count from the beginning is 10. hence divide by 10.
  we need to divide 2888/10, the quotient is 2, hence 2 is the number.
  you can verify it for other values also.
  let's say what is the 32nd digit.
  32/10 gives quotient 3, hence result is 3.
  40th digit:- 40/10=4, hence 40th digit is 4.
• 9 years agoHelpfull: Yes(2) No(3)
• 1*1(times1)2*1(times2)3*1(times3)4*1(times4)1*2(times1)2*2(times2)3*2(times3).....
  taking 1*1(times1)2*1(times2)3*1(times3)4*1(times4) as one term.
  The sum of first term is 10 next is 20...
  1 st term is multiplied by 1.(1*10).
  2 nd term is multiplied by 2 (2*10).
  280 term will be multiplied by 28.
  now next term will be multiplied by 29.
  so 29(1's),(2*29)(2's)=87.
  so next will be 3.
  Hence 3 is the solution.
• 9 years agoHelpfull: Yes(1) No(1)
• 3
  by making the program in java
• 9 years agoHelpfull: Yes(0) No(4)
• sorry
  =2560+338=2888 [336
• 9 years agoHelpfull: Yes(0) No(0)
• =2560+328=2888 [336
• 9 years agoHelpfull: Yes(0) No(0)
• 4 is the answer
• 9 years agoHelpfull: Yes(0) No(1)
• ans is 3 by converting into gp
• 9 years agoHelpfull: Yes(0) No(0)