Of 38 people in my office, 10 like to drink chocolate,15 are cricket fans and 20 neither like chocolate nor like cricket, how many people like both cricket and chocolate?

a. 7
b. 10
c. 15
d. 18

• 20 neither like chocolate nor cricket
  therefore,people likes either chocolate or cricket are+38-20=18
  so, now pele like both=people like chocolate + peole likes cricke -
  people like either chocolate or cricket
  =10+15-18
  =7
  so,option a) is the correct ans.
  
• 10 years agoHelpfull: Yes(54) No(1)
• Total=10 like to drink chocolate+15 are cricket fans+20 neither like nor both
  TOTAL=P[A]+P[B]-LIKE BOTH A AND B
  AUB=P[A]+P[B]-[38-20]
  =25-18
  Ans=7
• 10 years agoHelpfull: Yes(18) No(0)
• 7 is the answer
  
  this can be solved by set theory
  
  let A be chocolate lovers
  let B be the cricket lovers
  let U be the total colleagues
  
  A = 10
  B = 15
  U - A union B = 20
  so, A union B = U - 20 = 38 - 20 = 18
  
  Now, we need to find A intersection B
  i.e.
  
  A intersection B = A + B - A union B
  => 10 + 15 - 18
  => 7
• 10 years agoHelpfull: Yes(6) No(1)
• Total=10 like to drink chocolate+15 are cricket fans+20 neither like both
  38=10+15+20
  38=45
  45-38=7
  Ans:7
• 10 years agoHelpfull: Yes(4) No(1)
• 38-20=18
  like chocolate 18-10=8
  like cricket 18-15=3
  like both chocolate and cricket 18-(8+3)=7
  ans :7//
• 10 years agoHelpfull: Yes(2) No(0)
• Let event A=people drinking chocolate
  B=people liking cricket
  so p(A)=10/38
  p(B)=15/38
  p(neither A nor B)=20/38
  P(either A or B)= 1-20/38=18/38
  P(both A and B)=10/38+15/38-18/38=7/38
  So,people liking both cricket and chocolate=7
• 10 years agoHelpfull: Yes(1) No(0)
• lets remaining peaple=38-20=18
  now 7+3=10
  7+8=15
  and 10+8=18=18(remaining people) so common is 7.
• 10 years agoHelpfull: Yes(1) No(0)
• a] 7
  using venn diagram
• 10 years agoHelpfull: Yes(0) No(0)
• 7
  no. of people who likes either is 38-20=18
  no. of people who likes only cricket = 18-10=8
  no of people who likes both = 15-8=7
• 10 years agoHelpfull: Yes(0) No(0)
• 1st term 10 ,2nd 20 .... now in this way 10+20+40+80+160+320+640+1280=2550
  and next 1s is 256 so 2550+256=2806
  2s term is 512 so 2806+512=3318
  so ans is 2 :)
  
• 10 years agoHelpfull: Yes(0) No(4)
• 15 p(aub)=p(a)+p(b)-p(a intersection b))
• 10 years agoHelpfull: Yes(0) No(1)
• ans is 7.....its right ans.
• 10 years agoHelpfull: Yes(0) No(0)
• p(a intersection b)=38-20=18
  10+15-18=7
• 10 years agoHelpfull: Yes(0) No(0)
• U=38
  n(choc)=10
  n(cric)=15
  n(neither choc nor cric)=20
  so, choc Union cric = U - n(neither choc nor cric)= 38-20=18
  hence ,choc Intersection cric = n(choc)+ n(cric)-n(choc union cric)
  =>10+15-18=7
  Ans-->> 7
  
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is 7
  Total people=38
  No of people like none=20
  So no of people like either one thing=38-20=18
  
  Probability of liking choc=10/38
  Probability of cric=15/38
  P of liking both =15/38+10/38-18/38=7/38
  Therefore people liking both is 7
• 10 years agoHelpfull: Yes(0) No(0)
• people like either chocolate or cricket
  =10+15-18
  =7
• 10 years agoHelpfull: Yes(0) No(0)
• n(Cricket)=15
  n(choc)=10
  number of people who either like chocolate or cricket = > n(Cricket U chocolate)= 38-20= 18
  n(Cricket∩Choc)= n(Cricket)+n(Choc)-n(Cricket U Choc)
  => 15+10-18=7
• 9 years agoHelpfull: Yes(0) No(0)
• n(AuB)=n(A)+n(B)-n(A&B)
  38-20=10+15-X
  18=25-X
  -7=-X
  X=7
  
• 9 years agoHelpfull: Yes(0) No(0)
• 15 bcz of a union b is equal to a plus b minus a intersetion b
• 9 years agoHelpfull: Yes(0) No(1)
• ans is 7 only
• 8 years agoHelpfull: Yes(0) No(0)