what is summation of K=0283K(28KC)
where 28KC is the number of ways of choosing k items from 28 items?
a)256
b)3*227
c)329
d)3*427

• option A is correct) 256
• 9 years agoHelpfull: Yes(2) No(2)
• 28CK I guess.
• 9 years agoHelpfull: Yes(1) No(3)
• Consider (1+x)n=C0+C1x+C2x2+.....+Cnxn .......(1)
  Differentiating w.r.t x we get
  n(1+x)n−1=C1+2C2x+3C3x2+.....+nCnxn−1
  Multiplying by x on both sides,
  x.n(1+x)n−1=x.C1+2C2x2+3C3x3+.....
  Now again differentiating w.r.t to x
  n(1+x)n−1+n(n−1)x(1+x)n−2=C0+22C1x+32C2x2+42C3x3.....
  Putting x = 1, we get
  n(n+1)2n−2=C1+22C2+32C3+42C4
  Now substituting n = 28
  28(28+1)228−2 = 812.226 = 406.227
• 9 years agoHelpfull: Yes(1) No(1)