there r 6 digits 1,2,3,4,5,6, a 5 digit number is to formed frm these digits which is divisible by 4

• 12,16,24,32,36,52,56,64 these 8 combination comes in place of
  last 2 digits...
  so
  4*3*2*8=192
• 10 years agoHelpfull: Yes(26) No(2)
• As we know that If last two digit of any no. is divisible by 4 then that number would be div. by 4.
  
  if repetition are not allowed.......
  5 digits numbers are
  i.)if last digits no. is 2 --------- 1 way
  2nd last digits would be 1,3 and 5 ---------- 3 ways
  first digit will be 4 out of 1 ----------4 ways
  second digit will be 3 out of 1 ----------3 ways
  third digit will be 2 out of 1 ----------2 ways
  now, 4*3*2*3*1 = 72
  now similarly we will put last digit 4.
  then no. of way will be 48.
  again last digit 'll be 6 then the no. of way 'd be 72.
  
  Hence, the total no of way is 72+48+72 = 192
  
  
  
• 10 years agoHelpfull: Yes(9) No(1)
• ans :- 192
• 10 years agoHelpfull: Yes(1) No(1)
• how? please explain it
• 10 years agoHelpfull: Yes(0) No(2)
• plz give the option
  
• 10 years agoHelpfull: Yes(0) No(1)
• 12 16 24 36 48 52 56 64 total 8 combinations possible,which is divisible by 4(lkast 2 digits shud be divsble by four).there are five digits the first three digits can be filled in 3! ways, ie 3*2*1 and the remaining two digits in 8 combinations. ie, 3!*8= 48
• 10 years agoHelpfull: Yes(0) No(2)