a contractor agreed to complete a work in 40 days.he engaged 25 men for the work and after 24 days,only one third of the work was completed.how many more men must he employ to complete the work 4days earlier?

• 25 men work in 24 days,and 1/3rd of work,
  remaining work= 1-1/3= 2/3
  4 days earlier =40-4=36,
  remaining days to work=36-24=12
  so , 12 men 2/3rd of work = (25*24*1/3) /(12*2/3)=100
  
  already 25 men worked, so added men is= 100-25=75
  
  
• 10 years agoHelpfull: Yes(1) No(0)
• 24*25=w/3
  w=24*25*3=1800 mandays
  work done=25*24=600 mandays
  remaining work= 1800-600= 1200 mandays
  and d work to be doing in 12 days so
  1200/12= 100 men will be required
  out of which 25 are already working
  so 100-25= 75 men more will be required
• 10 years agoHelpfull: Yes(0) No(0)
• 75 men
  
  25 men's, 24 day work= 1/3
  25 men's, 1 day work= 1/(3*24)
  1 man's, 1 day work= 1/(3*24*25)
  Work remaining= 2/3 and is to be completed in total 40-4=36 days
  As already 24 days are over, so if 'x' more men are employed, then, existing 25 men & extra 'x' men should work for 36-24= 12 days.
  12/(3*24) + 12*x/(3*24*25) =2/3
  On solving, x=75
  
• 10 years agoHelpfull: Yes(0) No(0)
• Work done by 25 men for 24 days = 25*24 men-days = 1200 men-days
  It is given that only 1/3rd work was done.
  
  Therefore, 33.33% work = 600 men-days
  or 1% work = 600/33.33 men-days
  
  Remaining work = 100-33.33 = 66.67
  
  so, 66.67% work = 1200*66.67/33.33 = 1200 men-days
  
  The work has to be completed before 4 days.
  It means 40-24-4 = 12 days are remaining to compete the work.
  
  1200 men-days = 100men * 12 days
  
  and 100-25 = 75 (because 25 men we already have)
• 10 years agoHelpfull: Yes(0) No(0)
• w=24*25*3=1800 mandays
  work done=25*24=600 mandays
  remaining work= 1800-600= 1200 mandays
  and d work to be doing in 12 days so
  1200/12= 100 men will be required
  out of which 25 are already working
  so 100-25= 75 men more will be required
  
• 10 years agoHelpfull: Yes(0) No(0)