find the missing terms in the series 1,23,109,307,665

• 1^3 - 0^2 = 1
  3^3 - 2^2 = 23
  5^3 - 4^2 = 109
  7^3 - 6^2 = 307
  9^3 - 8^2 = 665
  
  next term = (11^3 - 10^2) = 1231
• 10 years agoHelpfull: Yes(25) No(0)
• 1 23 109 307 665
  22 86 198 358
  64 112 160
  48 48
  So the 3rd difference is in AP with differencr 48
  Next term of 3rd row 160+48 = 208
  Next term of 2nd row 208+358 =566
  Next term of 1st row 665+556 =1231
• 8 years agoHelpfull: Yes(4) No(0)
• 1231
  
  11^3-10^2
• 10 years agoHelpfull: Yes(0) No(1)
• the sequence is 1,23,109,307,665,1231
  first term = 1^3-0^2
  second term = 3^3-2^2
  last term = 11^3-10^2
• 10 years agoHelpfull: Yes(0) No(0)
• 1231,because the last term of the series,expression is 11^3-10^2
• 10 years agoHelpfull: Yes(0) No(0)
• 1^3 - 0^2 = 1
  3^3 - 2^2 = 23
  5^3 - 4^2 = 109
  7^3 - 6^2 = 307
  9^3 - 8^2 = 665
  
  next term = (11^3 - 10^2) = 1231
• 10 years agoHelpfull: Yes(0) No(0)
• Thank you Sohini Chakraborty
• 7 years agoHelpfull: Yes(0) No(0)
• 1 23 109 307 665
  22 86 198 358
  64 112 160
  48 48
• 6 years agoHelpfull: Yes(0) No(0)