X is d product of all the integers from 300 to 400.
Y is d product of all the integers from 300 to 401.
what is (1/x + 1/y) in terms of Y?

• From the ques x=300*3001*302.....*400
  Y=300*301*302......*401
  (1/x+1/y)
  =(401+1)/y because x,y's LCM is y..
  =402/y
  Ans. 402/y.
• 9 years agoHelpfull: Yes(51) No(0)
• Answer is 402/y .
  Explanation : x is product of all the integers from 300 to 400
  y is the product of all the integer from 300 to 401.
  so we can write x = y/401
  so
  1/x + 1/y
  = 1/(y/401) + 1/y
  = 401/y + 1/y
  402/y
• 9 years agoHelpfull: Yes(19) No(0)
• x=300*301*302.....*400
  y=300*301*302.....*400*401
  let 401=d
  y=x*d
  now
  (1/x+1/y)=(x+y)/x*y=(1=d)/y=(1+401)/y
  ans is 402/y
• 9 years agoHelpfull: Yes(3) No(0)
• x=300*301....399*400
  y=300*301*....400*401
  
  now 1/x + 1/y = (401+1)/(300*301....401) = Y+1/Y
• 9 years agoHelpfull: Yes(2) No(5)
• we have to represent 402 also in terms of Y thats the question.If it is not then its not an elitmus level questions.
• 8 years agoHelpfull: Yes(1) No(2)