Elitmus
Exam
Numerical Ability
Geometry
X is d product of all the integers from 300 to 400.
Y is d product of all the integers from 300 to 401.
what is (1/x + 1/y) in terms of Y?
Read Solution (Total 5)
-
- From the ques x=300*3001*302.....*400
Y=300*301*302......*401
(1/x+1/y)
=(401+1)/y because x,y's LCM is y..
=402/y
Ans. 402/y. - 10 years agoHelpfull: Yes(51) No(0)
- Answer is 402/y .
Explanation : x is product of all the integers from 300 to 400
y is the product of all the integer from 300 to 401.
so we can write x = y/401
so
1/x + 1/y
= 1/(y/401) + 1/y
= 401/y + 1/y
402/y - 10 years agoHelpfull: Yes(19) No(0)
- x=300*301*302.....*400
y=300*301*302.....*400*401
let 401=d
y=x*d
now
(1/x+1/y)=(x+y)/x*y=(1=d)/y=(1+401)/y
ans is 402/y - 10 years agoHelpfull: Yes(3) No(0)
- x=300*301....399*400
y=300*301*....400*401
now 1/x + 1/y = (401+1)/(300*301....401) = Y+1/Y - 10 years agoHelpfull: Yes(2) No(5)
- we have to represent 402 also in terms of Y thats the question.If it is not then its not an elitmus level questions.
- 9 years agoHelpfull: Yes(1) No(2)
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