Elitmus
Exam
Category
if mod(x-4)+mod(y-4)=4, then how many integer values can the set (x,y) have?
Read Solution (Total 10)
-
- only 16 integral soln.
|x-4|+|y-4|= 4
x & y can have values from 0 to 8 only.
for x=0 & x =8 , only 1 soln in each case
for x = 1 to 7 , two solns for each values of x.
total = 2 + 2*7 = 16 soln.
check:
if x = 0 , y = 4
if x = 1 , y = 3,5
if x = 2 , y = 2,6
if x = 3 , y = 1,7
if x = 4 , y = 0,8
if x = 5 , y = 1,7
if x = 6 , y = 2,6
if x = 7 , y = 3,5
if x = 8 , y = 0
- 10 years agoHelpfull: Yes(15) No(3)
- |x-4|+|y-4|=4
x=0,y=4 (1)
x=1,y=3,5 (2)
x=2,y=2,6 (2)
x=3,y=1,7 (2)
x=4,y=0,8 (2)
x=5,y=1,7 (2)
x=6,y=2,6 (2)
x=7,y=3,5 (2)
x=8,y=4 (1)
than total solution should be 16.
- 10 years agoHelpfull: Yes(3) No(0)
- Answer will be 14
If we solve the equation then we will get the equation: x+y=12,Now the possible pairs are (0+12),(1+11),(2+10),(3+9),(4+8),(5+7),(6+6),(6+6),(7+5),(8+4),(9+3),(10+2),(11+1),(12+0),which is equal to 14.......pls crct me if m wrng - 10 years agoHelpfull: Yes(2) No(0)
- 16 integral solution
if x = 0 , y = 4
if x = 1 , y = 3,5
if x = 2 , y = 2,6
if x = 3 , y = 1,7
if x = 4 , y = 0,8
if x = 5 , y = 1,7
if x = 6 , y = 2,6
if x = 7 , y = 3,5
-->> if x = 8 , y = 4 ...... - 10 years agoHelpfull: Yes(2) No(1)
- here is two diffrent variable...then every value of x,y has a unique value...that means it has infinite set of solution.
- 10 years agoHelpfull: Yes(0) No(3)
- ANSWER==> 16
there are 16 solutions,
possible combinations are (4+0),(3+1),(2+2), (0+4)
now, for 4+0
X can be 8 or 0 then Y can be 4. So 2 set of values
similarly for 2+2 there are 4 set of values
now adding all the sets of values for all 4 possible combination
we get 16 set of values - 10 years agoHelpfull: Yes(0) No(4)
- ans-40
since there will be two equations. one will be in +ve and other one will be in -ve. and since it is an integer it will take both =ve and -ve set of values.
|x-4|+|y-4|=4 and -|x-4|-|y-4|.
- 10 years agoHelpfull: Yes(0) No(0)
- x-4+y-4=4
x+y=12
possible pairs of (x,y) are (0,12),(1,11),(2,10),(3,9),(4,8),(5,7),(6,6),(7,5),(8,4),(9,3),(10,2),(11,1),(12,0)
so there are 13 solutions - 10 years agoHelpfull: Yes(0) No(0)
- ans-38, there will be two equations
- 10 years agoHelpfull: Yes(0) No(0)
- |x-4|+|y-4|=4
case 1
if x,y>=4
(x-4)+(y-4)=4, x+y=12
At that case possible pair of (x,y) is (4,8),(5,7),(6,6),(7,5),(8,4)
case 2
if x=4
-(x-4)+(y-4)=4, y-x=4
At that case possible pair of (x,y) is (0,4),(1,5),(2,6),(3,)
case 3
if x>=4,y - 10 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question