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which is the highest 3 digit number that divides nnumber 111....1(27 times ) perfactly without leaving remainder.
Read Solution (Total 9)
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- 999
111....1(27 times )
divisble by 111
& 9 also as sum of digits = 27
reqd no. = 9*111 = 999 - 10 years agoHelpfull: Yes(48) No(0)
- Ans:999
highest 3 digit number is 999
111...1(27 times)
Sum of digit is=27
999 sum of digit is=27
so 27/27=1
@RISHABH
111 is correct..read the question they asking highest 3 digit number so 999 is Ans - 10 years agoHelpfull: Yes(14) No(0)
- 999
111....1(27 times )
divisble by 111
& 9 also as sum of digits = 17
reqd no. = 9*111 = 999 - 10 years agoHelpfull: Yes(2) No(1)
- 111...(27 times) is divisible by 111
thus leaving 111..(9 times)
111...(9 times) is divisible by 9 also
so 111*9 completely divides 1111...(27 times). - 10 years agoHelpfull: Yes(2) No(0)
- Take 111
Sum of digit is 3
=27/3=9
- 10 years agoHelpfull: Yes(1) No(1)
- 111
since 11111........27 times divided it leaves no remainder.
- 10 years agoHelpfull: Yes(0) No(2)
- Ans is 999
1+1+1+......+1(upto 27 times)=27
9+9+9=27
so, 27/27=1... No reminder.. - 10 years agoHelpfull: Yes(0) No(0)
- I dnt get any of the solutions...wat would b the answer if it is said to find the highest 3-digit no. That divides 11111...1(21 times)..
Pls explain) - 10 years agoHelpfull: Yes(0) No(0)
- 11111....../999=1
- 10 years agoHelpfull: Yes(0) No(0)
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