which is the highest 3 digit number that divides nnumber 111....1(27 times ) perfactly without leaving remainder.

• 999
  
  111....1(27 times )
  
  divisble by 111
  & 9 also as sum of digits = 27
  
  reqd no. = 9*111 = 999
• 9 years agoHelpfull: Yes(48) No(0)
• Ans:999
  
  highest 3 digit number is 999
  111...1(27 times)
  Sum of digit is=27
  999 sum of digit is=27
  so 27/27=1
  
  @RISHABH
  111 is correct..read the question they asking highest 3 digit number so 999 is Ans
• 9 years agoHelpfull: Yes(14) No(0)
• 999
  
  111....1(27 times )
  
  divisble by 111
  
  & 9 also as sum of digits = 17
  
  reqd no. = 9*111 = 999
• 9 years agoHelpfull: Yes(2) No(1)
• 111...(27 times) is divisible by 111
  thus leaving 111..(9 times)
  111...(9 times) is divisible by 9 also
  so 111*9 completely divides 1111...(27 times).
• 9 years agoHelpfull: Yes(2) No(0)
• Take 111
  Sum of digit is 3
  =27/3=9
  
  
• 9 years agoHelpfull: Yes(1) No(1)
• 111
  since 11111........27 times divided it leaves no remainder.
  
• 9 years agoHelpfull: Yes(0) No(2)
• Ans is 999
  
  1+1+1+......+1(upto 27 times)=27
  9+9+9=27
  so, 27/27=1... No reminder..
• 9 years agoHelpfull: Yes(0) No(0)
• I dnt get any of the solutions...wat would b the answer if it is said to find the highest 3-digit no. That divides 11111...1(21 times)..
  Pls explain)
• 9 years agoHelpfull: Yes(0) No(0)
• 11111....../999=1
• 9 years agoHelpfull: Yes(0) No(0)