find highest power of 2 in 1 2 3 4 600

ansr is 0.
since every factorial from 2! onwards upto 600! is even and we sum it such that:2!+3!+.......600!=even
now this even+1!=odd (since 1! is odd)
and so odd number has no power of 2 ,hence answer is 0.
10 years agoHelpfull: Yes(39) No(0)
2!=2,3!=6;4!=24;5!=120;6!=120......600! also even number
even+even=even
so 1!=1
add 1 to all the sum it is odd:: so, there is no factor of 2
highest power of 2=0;
10 years agoHelpfull: Yes(13) No(0)
Here , sum of 2!+3!+...+600! = 4+6+...+600! = It will give a even no .
But if I add 1! with this then it Will be an odd number.

( 1! ) + (2!+3!+...+600! ) = even + odd = odd .

And also we know that odd no does not contain any 2 .
As we know ( number % 2 == 0)
{
even no ;
}
else
{
odd no;
}
So the sum of 1!+2!+3!+...+600! does not contain any 2 .
So it will be 2^0 .
10 years agoHelpfull: Yes(4) No(0)
from 5! onwards last digit will be 0. Therefore we need to check the last digit of 1!+2!+3!+4!=33. Which is odd
Therefore ans is 0
10 years agoHelpfull: Yes(2) No(0)
how u r saying that s odd?
i cant get u..plz explain.
10 years agoHelpfull: Yes(1) No(0)
0 ans
no power of 2
so zero
10 years agoHelpfull: Yes(0) No(0)
2^300..highest power of 2 is 300
10 years agoHelpfull: Yes(0) No(1)
ANS IS 0
UNIT DIGITS SUM IS ODD SO 2^0=0
10 years agoHelpfull: Yes(0) No(0)

find highest power of 2 in 1!+2!+3!+4!...........+600!