if the average of 4 different integers is 75 .of the largest integer is 90,what is the least possible value of the smallest integer?

• Answer:33
  total sum of 4 different integers=4*75=300
  largest one is 90 so 300-90=210 is total sum of remaining 3 different integers.
  so 89+88+33=210...so 33 is the answer
• 9 years agoHelpfull: Yes(9) No(0)
• 4*75=300
  90+89+88+x=300
  x=300-267
  x=33 smallest number
• 8 years agoHelpfull: Yes(3) No(0)
• smallest no may be 32
• 9 years agoHelpfull: Yes(0) No(1)
• Answer:60
  4 numbers are:60,70,80,90
  
• 9 years agoHelpfull: Yes(0) No(1)
• 4 numbers are:60,70,80,90, so ans = 60
• 9 years agoHelpfull: Yes(0) No(1)
• ans-60
  largest no.=90
  so smallest can be 15 less than 75 as 90 is 15 greater than 75.
  i.e.75-15=60
• 8 years agoHelpfull: Yes(0) No(0)
• answer is 60. let x be smallest number
  x+90=75*2
  x=150-90
  x=60
• 8 years agoHelpfull: Yes(0) No(0)
• 33 (x+y+z+90)/4=300
  x+y+z=210
  if x should be min then y n z should be as large as possible i.e y=88, z=89
  hence solving for equation x=33
• 8 years agoHelpfull: Yes(0) No(0)