Three vessels having volumes in the ratio of 1:2:3 are full of mixture of coke and soda. In the first vessel ratio of coke and soda is 2:3 in second ,3:& and in the third 1:4 if the liquid in all the three vessels were mixed in bigger container what is the resulting mixture of coke and soda.

• Let us consider volumes of the 3 vessels as:-
  Vessel 1: 10x
  vessel 2: 20x
  vessel 3: 30x
  
  Therefore,
  
  Coke1(Coke in vessel1)= 2/5*10x = 4x
  Soda1= 3/5*10x = 6x
  
  Similarly,
  Coke2= 6x ; Soda2 = 14x
  and
  Coke3= 6x ; Soda3 = 24x.
  
  Therefore on mixing,
  total soda = 44x
  total coke = 16x
  
  Thus,
  
  Coke : Soda = 16x : 44x = 4 : 11
• 9 years agoHelpfull: Yes(16) No(0)
• let volume of 1st can is 10 ltr ,2nd can is 20 ltr and 3rd can is 30 ltr
  coke in 1st can is 4 ltr
  soda in 1st can is 6 ltr
  coke in 2nd can is 6 ltr
  soda in 2nd can is 14 ltr
  coke in 3rd can is 6 ltr
  soda in 3rd can is 24 ltr
  resulting ratio of coke and soda=(4+6+6):(6+14+24)=16:44=4:11
• 9 years agoHelpfull: Yes(8) No(0)
• consider that the vessels had x,2x and 3x volume of mixtures
  now
  1st vessels:
  has
  2p and 3p amount of coke n soda
  2nd vessel:
  3p and 7p(i thought 7 is mistyped as"&")
  3rd vessel:
  1p and 4p
  
  now in the total mixture we hv
  coke=(x*2p)+(2x*3p)+(3x*p)=11px
  soda=3xp+14xp+12xp=29xp
  
  so now coke :soda=11:29
• 9 years agoHelpfull: Yes(6) No(8)
• RATIO OF VOL. OF VESSEL=1:2:3
  1).COKE:SODA=2:3
  2X+3X=1
  X=1/5
  SO...COKE=2X=2/5 AS WELL AS SODA=3/5
  2.C:S=3:7
  3X+7X=2
  X=1/5
  SO..C=3/5 AS WELL AS S=7/5
  3).c:s=1:4
  1X+4X=3
  X=3/5
  SO C=3/5 AS WELL AS S=12/5
  TOTAL COKE:TOTAL SODA=2/5+3/5+3/5:3/5+7/5+12/5=8/5:22/5=4:11
• 8 years agoHelpfull: Yes(1) No(0)
• 4/11
  5+10+5=20
  Now divide 20 in the given ratio & calculate for each vessel
• 9 years agoHelpfull: Yes(0) No(1)