A B and C run a race with A finishing 48 meters ahead of B and 72 meters ahead of C while runner B finishes 32 meters ahead of runner C.Each runner travels the entire distance at a constant speed .What is the length of the race

• when B covers 48 m to finish, C covers (72-32)=40 m
  So, ratio of speed of B to C is 48:40 i.e. 6:5
  distance ratio also same, because time same.
  Let's assume total distance is 6x
  So, (Distance by B)-(Distance by C)=32
  6x-5x=32
  x=32
  6x=192 meter
  but other multiple of 32 also possible
  
  Answer=32n meters where n>=3 (3,4,5......)
  
• 10 years agoHelpfull: Yes(9) No(2)
• when A finishes B has to cover 48m and C has to cover 72m.
  After A finishes race when B finishes race he covers 48m in same time C covers 72-32=40m.
  So ratio of their speed is b/c=48/40=6/5.
  
  Now l/b=(l-32)/c. (equting time when b , c finishes race)
  and b/c=6/5
  on solving we get l=192
• 10 years agoHelpfull: Yes(7) No(0)
• Ans:192M
  Length of the race 192 m
  When A run 192m
  B run 144m
  C run 120m
  .............
  Condition 1
  A finishing 48 meters ahead of B
  192-144=48 So Condition 1 is True
  .............
  Condition 2
  72 meters ahead of C
  192-120=72 Condition 2 is True
  .............
  When B Covered 192m C would Cover 160
  B can give C a start of 32m
• 10 years agoHelpfull: Yes(5) No(1)
• length of race is 80 m ...
  equating the time we get
  (l-48)/sb =l/sa ----1)
  (l-72)/sc =l/sa ----2)
  l/sb =(l-32)/sc ----3)
  on solving these three we get value of l =80 m
• 10 years agoHelpfull: Yes(2) No(8)
• let us consider x as length of the race
  when A finishes the race,b is 48m ahead & C is 32m ahead
  when B finishes the race,C is 72-32=40m ahead
  so it is in the ratio=48:40=6:5
  (x-48)/(x-72)=6/5
  x=120(length of the race)ans
  
  
• 10 years agoHelpfull: Yes(1) No(0)
• take total dist=x
  a/b=x/x-48
  a/c=x/x-72
  b/c=x/x-32=x-48/x-72
  by solving we get x=192
  
• 10 years agoHelpfull: Yes(1) No(0)
• length of race is 84 m
  in second statement b finsihes 48 meter while c finshes only 16 m in same time
  so if we let speed of c is 1m/minute then b's speed is 3m/minute
  diff per minute betw b and c is 2 meter
  so in first statement diff is 24 meter i.e. b travelld 12 minutes and a and c also travelled 12 minutes...
  now diif betw a and b is 48 meter in 12 minutes in first minute
  so diff betw them per minute is 4 meter
  so speed of a=b+4=7 meter per minute
  so length of race=a's speed * time taken by a=7*12=84m
• 10 years agoHelpfull: Yes(0) No(3)
• Ans: 192 Unit
  Let total distance= X
  (X-72)*X /(X-48) = (X-32)
  after solving:
  X=192 unit
• 10 years agoHelpfull: Yes(0) No(0)