(a% of a)+(b% of b)=2% of ab then what is the % of a is b?

• a*a/100+b*b/100=2a*b/100
  so (10a-10b)2
  ie a=b
• 10 years agoHelpfull: Yes(10) No(0)
• (a% of a)+(b% of b)=2%
  (100%of100)+(100%of100)=2
  (100+100)=2x
  200=2x
  x=100%
  
• 10 years agoHelpfull: Yes(9) No(2)
• the gvn eq gives
  a^2 + b^2=2ab
  which is (a-b)^2
  hence a=b
  100%
• 10 years agoHelpfull: Yes(4) No(0)
• (a% of a)+(b% of b)=2% of ab
  ie a^2 + b^2 =2ab
  ie (a-b)^2 =0
  ie a-b=0
  a=b
  ie 100%
• 10 years agoHelpfull: Yes(3) No(0)
• (a/100)*a+(b/100)*b=(2/100)*ab
  =) a=b
  hence 100%
• 10 years agoHelpfull: Yes(1) No(0)
• the gvn eq gives
  a^2 + b^2=2ab
  which is (a-b)^2
  hence a=b
  100%
• 10 years agoHelpfull: Yes(0) No(0)
• a/100*a +b/100*b= a^2/100 +b^2/100
  now, a^2/100 +b^2/100= 2ab/100
  which implies a^2+b^2=2ab
  => (a-b)^2=0
  => a=b
  therefore 100% of a is b
• 10 years agoHelpfull: Yes(0) No(0)
• a%a=a^2/100
  b%b=b^2/100
  2%ab=2ab/100
  now from given equation,
  a^2/100+b^2/100=2ab/100;
  or, a^2+b^2-2ab=0;
  or, (a-b)^2=0;
  a=b;
  so
  % of a is b will be 100%
  ans=100%
• 10 years agoHelpfull: Yes(0) No(0)
• a= 100% of b
• 10 years agoHelpfull: Yes(0) No(0)