a,b,c,d,e sitting in a row what is the probability that a & b sitting adjacent...

• total number of arrangement is= 5!= 120
  Favorable event i.e a and b can be arranged in 2! and the remaining can be arranged in 4! since ab can be in any of the four positions.
  so 4!*2!/5! = 2/5
• 10 years agoHelpfull: Yes(14) No(1)
• a,b,c,d,e a and b are adjacent means these two positions are fixed these can be arranged in 2! =2
  remaining 3 positions will be there these can in 3!==6
  3!*2!/5!=1/10
  
• 10 years agoHelpfull: Yes(9) No(11)
• 2/5
  5 people can be arranged in 120 ways
  In which a and b can be sitting adjacent in 48 ways.
  probability =48/120=2/5
• 10 years agoHelpfull: Yes(8) No(0)
• a,b,c,d,e but we have to see a anb stting together so consider ab one unit then the string can be formulated 4! ways and before 5! so probability 4!/5!=0.2
  
• 10 years agoHelpfull: Yes(2) No(3)
• ANS :
  Total arrangements = 5!
  Arrangements with a and b adjacent = 2*4!
  Probability = 48/120 = 2/5
• 9 years agoHelpfull: Yes(1) No(0)
• Total number of combination in which any two are together = C(5,2)=30
  Let us assume that a and b are one element than the total number places for them = 4
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  Thus probability of a & b sitting adjacent = 4/30 = 2/15
• 10 years agoHelpfull: Yes(0) No(5)
• cant b a c d e be an order ? is it oly supposed to be with a starting?
• 10 years agoHelpfull: Yes(0) No(4)
• 4!+2!
  4! is becz we will ve to take ab as 1 factor.
  and 2! becz they can be arranged themselves.
  which comes to 26
  then prob is 26/5! = 13/120
• 9 years agoHelpfull: Yes(0) No(0)